Answer:
see below
Step-by-step explanation: 5 27 7 16
area = 1/2 bh
height of a triangle is 7 ft more than its base
base = b
height = b + 7
area = 30
area = 1/2 b(h)
30 = 1/2 b(b + 7)
30 = 0.5(b²+ 7b)
30 = 1/2 b²+ 3.5b solve for b
1/2 b²+ 3.5b = 30
1/2 b²+ 3.5b - 30 = 0
b²+ 7b - 60 = 0 factor
(b +12)(b - 5) = 0 when b = -12 or 5 base length can't be negative
b = base = 5
area = 1/2 bh 1/2×2(9) = 9
area = 1/2 bh 1/2×5(12) = 60
area = 1/2 bh 1/2×9(16) = 56
area = 1/2 bh 1/2×12(19) = 114
A composite number is a number with more than 2 factors and 16, 18, 20, and 21 are composite.
Answer:
25%
Step-by-step explanation:
100%-30%=70%
70%-45%=25%
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
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* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
