I think its D but I'm not sure
3x +6= 2y-6+6. 6x-7=-7+7-5y
3x +6=2y. 6x -7=5y
÷2 = ÷2. ÷5 = ÷5
3/2x + 3= y. 6/5x - 7/5 = y
For this case we have the following function that models the problem is:
![y = 10 + 95x-16x ^ 2 ](https://tex.z-dn.net/?f=y%20%3D%2010%20%2B%2095x-16x%20%5E%202%0A)
The time for which the maximum height occurs is obtained by deriving the equation:
![y '= 95-32x ](https://tex.z-dn.net/?f=y%20%27%3D%2095-32x%0A)
We equal zero and clear x:
![95-32x = 0 32x = 95 x = 95/32 x = 2.97 ](https://tex.z-dn.net/?f=95-32x%20%3D%200%0A%0A%2032x%20%3D%2095%0A%0A%20x%20%3D%2095%2F32%0A%0A%20x%20%3D%202.97%20%0A)
The maximum height is obtained by evaluating the time obtained in the given equation:
![y = 10 + 95 * (2.97) -16 * (2.97) ^ 2 y = 151.02](https://tex.z-dn.net/?f=y%20%3D%2010%20%2B%2095%20%2A%20%282.97%29%20-16%20%2A%20%282.97%29%20%5E%202%0Ay%20%3D%20151.02)
Then, by the time it reaches the ground we have:
![10 + 95x-16x ^ 2 = 0 ](https://tex.z-dn.net/?f=10%20%2B%2095x-16x%20%5E%202%20%3D%200%0A)
From here, we clear x solving the quadratic equation:
![x = \frac{-95+/- \sqrt{95^2-4(-16)(10)} }{2(-16)}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Cfrac%7B-95%2B%2F-%20%5Csqrt%7B95%5E2-4%28-16%29%2810%29%7D%20%7D%7B2%28-16%29%7D%20)
We discard the negative root, and obtain as a result:
Answer:<span>
2.The pumpkin's maximum height is 151.02 feet and it hits the ground after 6.04 seconds </span>
Hmm
that is a true statement, the product of any 2 mixed numbers between 4 and 5, will be between 16 and 25
we can show that it is true by testing the bounds
if the number is 4 and the other is 4, then it is 16
we aren't allowed to do 4 since it isn't mixed and it equals 4
that is the lower bbound
if the numbes 5 and 5 are used, then it is 25
we arene't allowed to use 5 since it isn't mixed and it equals 5
so the product of any 2 numbers between 4 and 5 will be between 16 and 25
so pick any random one
4 and 3/4 times 4 and 5/323
Answer:
C. 2144
Step-by-step explanation:
I searched it up