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Slav-nsk [51]
3 years ago
6

The long side of a rectangle is 3x+21 units, and it's area is 3x^2+33x+84. Find the width

Mathematics
1 answer:
ella [17]3 years ago
3 0
L*w=area
(3x+21)*w=3x^2+33x+84
w=(3x^2+33x+84)/3x+21
(3(x+4)(x+7))/3(x+7)
w=x+4
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If the circumference of two circle are in the ratio 2:3, then their areas are in the ratio of
maxonik [38]

Answer:

4:9

Step-by-step explanation:

To take the scale factor from distance to area, we square it

2:3  distance

Square each term

2^2 : 3^2  area

4:9

6 0
3 years ago
If point C (3, 8) is reflected over the y axis what would be point C'?<br>no links please ​
olga2289 [7]

Answer:

(-3,8)

Step-by-step explanation:

When reflecting over the y-axis, you are switching from positive to negative x-values. Since 3 was already positive, we change the integer and in this case, to negative, so it becomes -3. Since the y value remains the same we don’t change the 8. So (-3,8)

I hope this helps!

Please give thanks or brainliest if this helps!

8 0
2 years ago
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Explain and find CD please
oksano4ka [1.4K]

Answer:

CD \approx5.29

Step-by-step explanation:

By geometric mean theorem:

CD=\sqrt {AD\times BD}  \\  \\ CD=\sqrt {7\times 4}  \\  \\ CD=\sqrt {28}  \\  \\ CD=5.29150262 \\  \\ CD \approx5.29

4 0
3 years ago
I’m trying to correct this problem but I don’t know how can someone help me
BartSMP [9]

Remark

It is not a straight line distance from the park to the mall. None of the answers give you that result. And if you know what displacement is, none of the answers are really displacement either. The distance is sort of a "as the crow flies." distance. There's a stop off in the middle of town.

Method

You need to use the Pythagorean Formula twice -- once from the park to the city Center and once from the city center to the mall.

Distance from the Park to the city center.

a = 3   [distance east]

b = 4  [distance south]

c = ??

c^2 = 3^2 + 4^2        Take the square root of both sides.

c = sqrt(3^2 + 4^2)

c = sqrt(9 + 16)          Add

c = sqrt(25)

c = 5

So the distance from the park to the city center is 5 miles

Distance from City center to the mall

a = 2 miles [distance east]

b = 2 miles [distance north]

c = ??

c^2 = a^2 + b^2   Substitute

c^2 = 2^2 + 2^2   Expand this.

c^2 = 4 + 4

c^2 = 8             Take the square root of both sides.

sqrt(c^2) = sqrt(8)

c = sqrt(8)          This is the result

c = 2.8

Answer

Total distance = 5 + 2.8 = 7.8

6 0
3 years ago
Help with these algebra 2 questions
monitta

Given\;:\sqrt{-18} - \sqrt{-32}

we know that i² = -1

\implies\sqrt{18}i - \sqrt{32}i\\

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6 0
3 years ago
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