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Slav-nsk [51]
3 years ago
6

The long side of a rectangle is 3x+21 units, and it's area is 3x^2+33x+84. Find the width

Mathematics
1 answer:
ella [17]3 years ago
3 0
L*w=area
(3x+21)*w=3x^2+33x+84
w=(3x^2+33x+84)/3x+21
(3(x+4)(x+7))/3(x+7)
w=x+4
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you will need to wait 3 hours and 30 mins

Step-by-step explanation:

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The mean annual income for people in a certain city is 37 thousand dollars, with a standard deviation of 28 thousand dollars. A
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Answer:

P( 31 < \bar X< 41)

And we can ue the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got for the limits:

z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515

z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01

So we want to find this probability:

P(-1.515

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the annual income of a population, and for this case we know the following info:

\mu=37 and \sigma=28  and we are omitting the zeros from the thousand to simplify calculations

We select a sample size of n=50>30.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P( 31 < \bar X< 41)

And we can ue the z score formula given by:

z= \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And using this formula we got for the limits:

z = \frac{31-37}{\frac{28}{\sqrt{50}}}= -1.515

z = \frac{41-37}{\frac{28}{\sqrt{50}}}= 1.01

So we want to find this probability:

P(-1.515

4 0
3 years ago
10 points
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Answer:

16 books fit and theres .8 inches left

Step-by-step explanation:

16x2.2 = 35.2

36 - 35.2 + 0.8

7 0
3 years ago
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A recent gasoline survey said that the national average price of gasoline was $1.298 a gallon. It was felt that gasoline price i
slava [35]

Answer:

<em>alternative hypothesis : H₁ :</em>

<em>Recent  Gasoline surveys felt that gasoline price in Texas was significantly lower than the national average</em>

<em>Alternative Hypothesis : H₁: μ < $1.298 a gallon</em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given A recent gasoline survey said that the national average price of gasoline was $1.298 a gallon

<em>Population average μ= $1.298 a gallon</em>

<em>sample size 'n' = 37</em>

<em>Sample mean (x⁻) = $1.192 a gallon </em>

<em>Sample standard deviation 'S' = $0.0436</em>

<em>Null hypothesis :H₀ : μ =  $1.298 a gallon</em>

<em>Alternative Hypothesis : μ < $1.298 a gallon</em>

<em>Degrees of freedom : ν = n-1= 37-1=36</em>

<em>t₀.₀₂₅ = 1.688</em>

<em>Test statistic </em>

<em>                        </em>t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }<em></em>

<em>                        </em>t = \frac{1.192-1.298 }{\frac{0.0436}{\sqrt{37} } }<em></em>

<em>                      t =  -14.8044</em>

<em>|t| = |-14.8044| > 1.688</em>

<em>Null hypothesis is rejected </em>

<em>Alternative hypothesis is accepted </em>

<em>Recent  Gasoline surveys felt that gasoline price in Texas was significantly lower than the national average</em>

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Answer:

Step-by-step explanation:

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37% of the cars were tan

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