3 different improper fractions that equal 4 2/3
1 answer:
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Answer:
Two options:
5,6, and 7
-1,0,and 1
Step-by-step explanation:
Three consecutive natural numbers can be represented as n, n+1, and n+2.
The product of the smaller two would be n(n+1). The less than 5 times the larger is 5(n+2)-5.
Set them equal and solve by factoring:
Set each factor equal to 0.
n-5==0 so n=5.
n+1=0 so n=-1.
This means the 3 consecutive numbers would be 5,6, and 7
OR
-1, 0 or 1.
Answer:
D. 6
Step-by-step explanation:
Let's first find x :-
Now that we found x, let's find QR :-
QR = 2x + 22
Therefore, QR = 6 !!!