Answer:
0
Step-by-step explanation:
Substitute x = 3 into the rational expression
![\frac{3^2-2(3)-3}{4(3)^2}](https://tex.z-dn.net/?f=%5Cfrac%7B3%5E2-2%283%29-3%7D%7B4%283%29%5E2%7D)
= ![\frac{9-6-3}{4(9)}](https://tex.z-dn.net/?f=%5Cfrac%7B9-6-3%7D%7B4%289%29%7D)
= ![\frac{0}{36}](https://tex.z-dn.net/?f=%5Cfrac%7B0%7D%7B36%7D)
= 0
Put the numbers from smallest to largest
1,2,5,8,10,15,16,20,22
subtract 22 from 1 to give you 21
the range is 21
The answer will be:- <u>x = 1</u>
15x^3-6x^2-35x+14 it that doesn’t work try mathaway
Plotting is the place the dots belong to?
If you want to do a positive of which is like (x,5) then you go to in between the right top and bottom or x axis where the positives are and count, if the (2,y) is positive you count and go up if y is a negative then you count down how many number there is.
Let’s use (1,-1) first you go into the x-axis, one is a positive so you go to one in there, and go down one or to -1 bc the -1 is a negative and the digit is 1. ( I hope it made sense, if u need more help u can tell me.)