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kari74 [83]
3 years ago
5

(20 x 40) x 14 = ?

Mathematics
2 answers:
sdas [7]3 years ago
4 0

Here is your answer:

(20 × 40) × 14 = 20 × 40 = 800 × 14 = 11200

According to PEMDAS P goes first, then multiply is by 14.

Therefore the answer is "11200."

Hope this helps!

fredd [130]3 years ago
3 0

To solve this problem, we must use the order of operations outlined by PEMDAS, which tells us that we should simplify or compute parentheses first, then exponents, multiplication, division, addition, and finally subtraction.

Using this method, we have to perform the multiplication inside the parentheses first.

(20 * 40) * 14

800 * 14

Finally, we must perform the final operation to simplify this expression, which is multiplication.

800 * 14 = 11200

Therefore, your final answer is 11200.

Hope this helps!

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c_1\left[\begin{array}{c}0\\0\\0\\1\end{array}\right] +c_2\left[\begin{array}{c}0\\0\\3\\1\end{array}\right] +c_3\left[\begin{array}{c}0\\4\\3\\1\end{array}\right] +c_4\left[\begin{array}{c}8\\4\\3\\1\end{array}\right] =\left[\begin{array}{c}0\\0\\0\\0\end{array}\right]

Then, the augmented matrix of the system is

\left[\begin{array}{cccc}0&0&0&8\\0&0&4&4\\0&3&3&3\\1&1&1&1\end{array}\right]

We exchange rows 1 and 4 and rows 2 and 3 and obtain the matrix:

\left[\begin{array}{cccc}1&1&1&1\\0&3&3&3\\0&0&4&4\\0&0&0&8\end{array}\right]

This matrix is in echelon form. Then, now we apply backward substitution:

1.

8c_4=0\\c_4=0

2.

4c_3+4c_4=0\\4c_3+4*0=0\\c_3=0

3.

3c_2+3c_3+3c_4=0\\3c_2+3*0+3*0=0\\c_2=0

4.

c_1+c_2+c_3+c_4=0\\c_1+0+0+0=0\\c_1=0

Then the system has unique solution that is (c_1,c_2c_3,c_4)=(0,0,0,0) and this imply that the vectors v_1,v_2,v_3,v_4 are linear independent.

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3 years ago
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