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3 years ago

How would you determine which x-values to use when creating a table of values to graph a parabola?

1 answer:

5 0

To determine which values of x we would use for creating a graph of a parabola, we need to know where the line of symmetry, or the axis of symmetry is. For that we can use the equation:

y=(x-h)+k, where we know h and k.

From this equation we can see that the line of symmetry is passing trough x=h.

And now we can determine which values do we need to add to h and to subtract from h to get values of x to create the table of values to plot a parabola.

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(8b^2/3*9t^3/5)(8b^5/3*9t^3/5)

erma4kov [3.2K]

Answer:

5,184•b•t^6/5

Step-by-step explanation:

Here, we want to multiply the expressions

According to indices law, if we have same bases, we add up the exponents

Thus, we have that;

8 *8b^(2/3+5/3) * 9 * 9 * t^(3/5+3/5)

= 64 * b * 81 * t^6/5

= 5,184bt^6/5

8 0

3 years ago

A bag contains tickets numbered 1 through 5. Use the probability distribution to determine the probability of drawing an odd num

Makovka662 [10]

Answer:

The probability of drawing an odd numbered ticket is 60%.

Step-by-step explanation:

Odd numbered tickets:

Probability of one is 1/5 plus half of 1/5.

$P(X = 1) = \frac{1}{5} + \frac{1}{10} = \frac{3}{10}$

Probability of 3 is half of 1/5.

$P(X = 3) = \frac{1}{10}$

Probability of 5 is 1/5. So

$P(X = 5) = \frac{1}{5}$

Probability of drawing an odd numbered ticket:

$p = P(X = 1) + P(X = 3) + P(X = 5) = \frac{3}{10} + \frac{1}{10} + \frac{1}{5} = \frac{4}{10} + \frac{2}{10} = \frac{6}{10} = 0.6$

0.6*100% = 60%

The probability of drawing an odd numbered ticket is 60%.

3 0

3 years ago

Which property justifies this statement?

lakkis [162]

the Reflexive Property of Equality

6 0

4 years ago

Read 2 more answers

There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f

Ann [662]

Answer:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated population proportion for this case is:

$\hat p = \frac{350}{500}=0.7$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.