Answer:
4 cm
Step-by-step explanation:
The midpoint segment has length ...
... L = AB/2 + BC + CD/2 = 16 cm
The entire segment has length ...
... AD = AB + BC + CD = 28 cm
If we subtract AD from 2L, we have ...
... 2L - AD - 2L = 2(AB/2 +BC + CD/2) - (AB +BC +CD) = 2(16 cm) -28 cm = 4 cm
... AB +2BC + CD -AB -BC -CD = 4 cm . . . . remove parentheses
... BC = 4 cm . . . . simplify
Answer:
Im sorry but are there any choices?
Step-by-step explanation:
Answer:
4
4+4-4=4 im not sure actually D:
A median is 65 inches and a standard deviation is 1.7:
a. 65 + 1 SD = 65 + 1.7 = 66.7 in
It means that there are : 100% - ( 50% + 34% ) = 100% - 84% = 16% students taller than 66.7 inches.
b. Heights between 61.6 in and 68.7 in are within 2 standard deviations:
13.5% + 34% + 13.5% + 34% = 95%
0.95 * 300 = 285
There are 285 students between 61.6 in and 68.7 in tall.