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Minchanka [31]
3 years ago
11

The gas station is 44 kilometers away. how far is the station in miles if 1 mile is 1.6 kilometers

Mathematics
1 answer:
kakasveta [241]3 years ago
7 0
There are  27.3403 miles in 44 kilometers
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Write a function rule for the output is 5 less than the input
san4es73 [151]

Answer:

y=x-5

Step-by-step explanation:

"output" means  y

and "input" means  x

So all you need to find is the =

Please mark brainliest and have a great day!

7 0
3 years ago
Brayden, Howard, and Vincent are on the football team. During a game, Brayden gains 1 less than 5 times the average number of ya
Gnoma [55]

Answer:  If two pair is parallel then it has no solution.

Step-by-step explanation:

Since we have given that

Let the number of gained yards by each player be y

For the case of Brayden:

Equation will be

y=5x-1\\\\y-5x=-1

For the case of Howard :

Equation will be

y=5x+1\\\\y-5x=1

For the case of Vincent :

y=4x+5\\\\y-4x=5

Since First two equations are parallel so it has no solution.

Reason:

y-5x=1\\\\y-5x=-1\\\\\frac{a_1}{a_2}=\frac{b_1}{b_2}=\frac{c_1}{c_2}\\\\\frac{1}{1}=\frac{5}{5}\neq \frac{1}{-1}

Hence, if two pair is parallel then it has no solution.


8 0
3 years ago
Read 2 more answers
Use the graph to answer F(-3)=
Virty [35]

Answer:

  f(-3) = 1

Step-by-step explanation:

The only point with an x-coordinate of -3 has a y-coordinate of 1. That is the value of the function f(x) for x=-3.

  f(-3) = 1

7 0
3 years ago
Read 2 more answers
Options are 264 414 2487 9948
Brums [2.3K]
Find total area

area=pir^2
d/2=r
12=d, 12/2=6=r

area=pi6^2=36pi, pi=3.14
area=113.04 square inches

22 per square inch

113.04 times 22=2486.88
rounded
2487 calories
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=5%28sin%28t%29%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%2Bycos%28t%29%29%29%3Dcos%28t%29%20%20%28sin%28
Nataliya [291]
Assuming you mean

5\sin t\dfrac{\mathrm dy}{\mathrm dt}+5y\cos t=\cos t\sin^2t

This ODE is linear in y, and you can already contract the left hand side as the derivative of a product:

\dfrac{\mathrm d}{\mathrm dt}\left[5y\sin t\right]=\cos t\sin^2t

Integrating both sides with respect to t yields

5y\sin t=\displaystyle\int\cos t\sin^2t\,\mathrm dt
5y\sin t=\dfrac13\sin^3t+C
y=\dfrac1{15}\sin^2t+C\csc t

Given that y\left(\dfrac\pi2\right)=9, we have

9=\dfrac1{15}\sin^2\dfrac\pi2+C\csc\dfrac\pi2
9=\dfrac1{15}+C
C=\dfrac{134}{15}

so that the particular solution over the interval is

y=\dfrac1{15}\sin^2t+\dfrac{134}{15}\csc t
6 0
3 years ago
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