I also need some help on this one. I need the area of the shaded region
1 answer:
What you have is, a circle inside an OCTAgon, OCTA=8 sides
so hmm get the area of the octagon, will include the area also of the circle,
then
get the area of the circle, and subtract it from the area of the octagon
what's left, is the "difference", or the shaded area
when taking the cotangent, make sure your calculator is in Degree mode, since the angle is in degrees
so hmm get the area of the octagon, will include the area also of the circle,
then
get the area of the circle, and subtract it from the area of the octagon
what's left, is the "difference", or the shaded area
when taking the cotangent, make sure your calculator is in Degree mode, since the angle is in degrees
You might be interested in
Ooh this is a good one!
Firstly, let's find RT so that we can solve the top triangle.
We could actually use 3 methods to find this side: 1) trig to find RT
2) trig to find ST, then Pythagorean Theorem to determine RT
3) use the special 30-60-90 right triangle rule ... hmm, I'm going with the last because it's easiest ;)
For 30-60-90 triangles, the sides are always as follows: smallest side (opposite the 30) is s, the middle side is sSR3, and the hypotenuse is 2×s
Thus, since we have the side opposite 60, it is = sSR3, so:
So now, the hypotenuse (RT) = 2s = 2(2) = 4
Secondly, we are looking at the other type of special right triangle, the 45-45-90:
The side opposite the 45s are s (remember side lengths are equal whose opposite angles are equal); and the hypotenuse is always
we only need QR, which is s, which is also = RT
So the answer is:
QR = x = 4
x = 4 IS THE FINAL ANSWER!!!
[ i hope by my explanations you understand how better to do special right triangles in the future] :-D
Firstly, let's find RT so that we can solve the top triangle.
We could actually use 3 methods to find this side: 1) trig to find RT
2) trig to find ST, then Pythagorean Theorem to determine RT
3) use the special 30-60-90 right triangle rule ... hmm, I'm going with the last because it's easiest ;)
For 30-60-90 triangles, the sides are always as follows: smallest side (opposite the 30) is s, the middle side is sSR3, and the hypotenuse is 2×s
Thus, since we have the side opposite 60, it is = sSR3, so:
So now, the hypotenuse (RT) = 2s = 2(2) = 4
Secondly, we are looking at the other type of special right triangle, the 45-45-90:
The side opposite the 45s are s (remember side lengths are equal whose opposite angles are equal); and the hypotenuse is always
we only need QR, which is s, which is also = RT
So the answer is:
QR = x = 4
x = 4 IS THE FINAL ANSWER!!!
[ i hope by my explanations you understand how better to do special right triangles in the future] :-D