Part (a): All are defective
Only one way of selecting the 5 defective transistors:
Number of ways of selections available = 6C5 = 16!/[5!*(15-5)!] = 4368
Probability they are all defective = Number of ways of selecting 5 defectives/Total number of ways possible = 1/4368 ≈ 0.000229
Part (b): None are defective
Total number of non defectives = 16 -5 = 11
Number of ways of selecting 5 non defective = 11C5 = 462 ways
Total number of ways possible = 16C5 = 4368
Probability of selecting 5 non defectives = 462/4368 = 11/104 ≈ 0.1058
The function f(x) = -5x³ + 3x² + x - 9 is a cubic function with the form:
f(x) = ax³ + bx² + cx + d, where a = -5, dictates the end behavoir of the function.
Since a is negative, then as x → -∞, y → ∞, and as x → ∞, y → -∞.
Answer:
this is your attachment ans
Answer:
x=4
Step-by-step explanation:
RS + ST = RT
5+ 2x-2 = 3x-1
Combine like terms
2x+3 = 3x-1
Subtract 2x from each side
2x+3-2x = 3x-1-2x
3 =x-1
Add 1 to each side
3+1 = x-1+1
4=x
