[9tan(θ) * 9cot(θ)] / 9sec(θ)
First cancel out the 9's:
tan(θ)cot(θ)/sec(θ)
Recall the following trig identities:
tan = sin/cos
cot = cos/sin
sec = 1/cos
Thus, we can rewrite the expression as:
[ (Sin(θ)/cos(θ)) *(cos(θ)/sin(θ)) ] / (1/cos(θ))
In the numerator, the sine's and cosine's cancel each other out:
1 / (1/cos(θ))
which we can rewrite as cos(θ).
Answer: 6/50
Step-by-step explanation:
N+2 because n is the smallest number
Answer:
D
Step-by-step explanation:
We are given that the side of a square is: 8√12.
And we want to find the area.
The area of a square is given by:
Where <em>s </em>is the side length. Remember that all side lengths in a square are equivalent.
Therefore, by substitution, we acquire:
Evaluate. We can expand:
Simplify:
Hence, our final answer is D.