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LUCKY_DIMON [66]
3 years ago
5

Triangle A B C is shown. Lines are drawn from each point to to the opposite side and intersect at point G. Line segments A D, B

E, and C F are created.
In triangle ABC, the segments drawn from the vertices intersect at point G. Segment FG measures 6 cm, and segment FC measures 18 cm.

Which best explains whether point G can be the centroid?

Point G cannot be the centroid because 18:6 does not equal 2:1.
Point G cannot be the centroid because FG should be longer than CG.
Point G can be the centroid because 12:6 equals 2:1.
Point G can be the centroid because FC is longer than FG.
Mathematics
1 answer:
REY [17]3 years ago
5 0

Answer:

Its C on edg 2020

Step-by-step explanation:

just did it

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A football field is 120 yards long and 160 yards wide. How many square yards of grass is needed to cover the field? Show your ca
sleet_krkn [62]

Answer:

19,200 yds²

Step-by-step explanation:

The question is asking for how many <em>square yards</em> of grass is needed

This means that it is looking for the Area.

The formula for area is <em>Length x Width = Area</em>

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<em>160</em> (Width)

<em>120 x 160</em> = 19,200

The unit of measurement is yards...

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8 0
3 years ago
The sum of 11.6 and 4.1 by rounding each number to the nearest whole.
Karo-lina-s [1.5K]
11.6 rounded to the nearest whole is 12 and 4.1 rounded to the nearest whole is 4 (rule is if the decimal [or number in general] is 4 or lower, the whole stays the same and if the number is 5 or higher, the whole goes up by one). 12+4=16
3 0
2 years ago
Solve the equation.
lawyer [7]

Answer:

  • x=12
  • x=9

Step-by-step explanation:

1) Eliminate parentheses:

  0.1x +18.8 = -4 +2x

  22.8 = 1.9x . . . . . . . . . add 4 - 0.1x

  12 = x . . . . . . . . . . . . . divide by 1.9

__

2) Eliminate parentheses:

  -16 +4x = 0.8x +12.8

  3.2x = 28.8 . . . . . . . . add 16 - 0.8x

  x = 9 . . . . . . . . . . . . . .divide by 3.2

_____

<em>Comments on the solutions</em>

The expression we add in each case eliminates the constant on one side of the equation and the variable term on the other side. That leaves an equation of the form ...

  variable term = constant

We choose to eliminate the smaller variable term (the one with the coefficient farthest to the left on the number line). Then the constant we eliminate is the on on the other side of the equation. This choice ensures that the remaining variable term has a positive coefficient, tending to reduce errors.

__

You can work these problems by methods that eliminate fractions. Here, the fractions are decimal values, so are not that difficult to deal with. In any event, it is good to be able to work with numbers in any form: fractions, decimals, integers. It can save some steps.

7 0
3 years ago
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