A line
A line has no width no height.
It has infinite length
Step-by-step explanation:
6. 4x−1−5x+17
=4x+−1+−5x+17
Combine Like Terms:
=4x+−1+−5x+17
=(4x+−5x)+(−1+17)
=−x+16
Answer:
=−x+16
7. (−x−3)−(5x−4)
Distribute the Negative Sign:
=−x−3+−1(5x−4)
=−x+−3+−1(5x)+(−1)(−4)
=−x+−3+−5x+4
Combine Like Terms:
=−x+−3+−5x+4
=(−x+−5x)+(−3+4)
=−6x+1
Answer:
=−6x+1
8. −9x+2−(−8x−2)
Distribute the Negative Sign:
=−9x+2+−1(−8x−2)
=−9x+2+−1(−8x)+(−1)(−2)
=−9x+2+8x+2
Combine Like Terms:
=−9x+2+8x+2
=(−9x+8x)+(2+2)
=−x+4
Answer:
=−x+4
Answer: .15x+2.00=2.75
5 days
Step-by-step explanation:
2.75-2.00= .75
.75/ .15= 5
Answer:
Range: 1 > x > 3
Step-by-step explanation:
We are given then function;
y = x³ - 6x² + 9x + 5
dy/dx = 3x² - 12x + 9
We want to find the range of values of x for which dy/dx > 0
Thus;
3x² - 12x + 9 > 0
Using quadratic formula, we have;
x = 1 and x = 3
Let's define the range;
try x = 0
3(0²) - 12(0) + 9 = 9
This is more than 0, so it is part of the solution.
Let's try x = 4
3(4²) - 12(4) + 9 = 9
This is more than 0 so it is part of the solution
Let's try x = 2
3(2²) - 12(2) + 9 = -3
This is less than 9 and so it's not part of the solution.
Thus the range of values of x for which dy/dx > 0 is;
1 > x > 3
3 because gravity pulls and when the diver jumps he get pulled down into the water. so the correct answer is c hope helped :)