Answer:
Step-by-step explanation:
Hello!
The experiment was designed to proof if the physiological blind spot can be reduced with eye training.
One sample of n people was taken and the physiological blind spot was measured. After that, the people selected underwent 3 weeks of eye training and their physiological blind spot was measured again. At the end of the experiment you have two sets of data for the sample, let's call X₁: physiological blind spot of one person before taking eye training", the measurements were taken before the training will correspond to this variable, and X₂: physiological blind spot of one person after three weeks of eye training" the second measurements correspond to this variable.
In this type of situation, where only one sample is taken and both variables are measured to the same observational unit (there is a pair of observations for each person), the observations are dependant and the corresponding test is the paired samples t-test.
To analyze the information you need to create a new variable, usually symbolized as Xd, that will be the difference between X₁ and X₂.
So your response variable would be
Xd: "Difference between a physiological blind spot of one person before taking eye training and physiological blind spot of after three weeks of eye training"
Xd= X₁ - X₂
The study parameter will be the mean of the variable "difference" μd.
I hope it helps!
The correct answer to this question is letter A which is visualizing. Visualizing is the act of picturing a certain situation in your head to recall how it works. In this example, you want to remember how a volcano functions. A volcano erupts. So in order to remember this, you picture in your mind a volcano that is erupting. So once you are asked a question about the functions of a volcano, your mind will immediately show the picture of a volcano erupting.
Answer:
I've attached the Answer
Step-by-step explanation:
here it is
If you're saying that the scale is 10 cm: 1 mm then the scale will be larger than the actual object because for every 1 mm of the object it will equal 10 cm of the scale drawing.
