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AleksandrR [38]
3 years ago
13

Write an equation and solve for the missing value show your work

Mathematics
1 answer:
ioda3 years ago
5 0
12x-5+85=128.......12x+80=128......12x+80-80=128-80....12x=48...... divide both sides by 12 to get x=4. Now most people do not complete solving for the missing value....12(4)-5=43 degrees
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Someone helppp!!!!!!
Yakvenalex [24]
Mother correct answer is -3,5
8 0
3 years ago
Is y= 1/2x - 4 equal to 3x - 6y = 24
Readme [11.4K]

Answer:

\fbox{\begin{minipage}{4em}Yes, it is\end{minipage}}

Step-by-step explanation:

3x - 6y = 24

Divide both sides by 6:

(3/6)x - (6/6)y = 24/6

Simplify:

(1/2)x - y = 4

Move y to the right side, 4 to the left side, and change sign of y and 4:

(1/2)x - 4 = y

Rearrange both sides:

y= (1/2)x - 4

Hope this helps!

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5 0
3 years ago
(PaperTowels)
DochEvi [55]

Answer:

<u>23 consumer.</u>

Step-by-step explanation:

Given:

Number Of Responses for Thirsty = 49

Number Of Responses for Clean = 24

Number Of Responses for Strong Ones = 15

Number Of Responses for PowerWash = 12

So,

The total number of Responses  = 49 + 24 + 15 + 12 = 100

So, the probability to prefer PowerWash = 12/100 = 0.12

For a group of 195 consumers:

prediction to prefer PowerWash paper towels = 0.12 * 195 = 23.4

So,

The number of consumers prefer PowerWash paper towels = <u>23 consumer</u>

7 0
4 years ago
Helppppppp pleaseeeeee
LenKa [72]

Answer:

4

Step-by-step explanation:

5 0
3 years ago
Listed below are the weights in pounds of 11 players randomly selected from the roster of the Seattle Sea-hawks when they won Su
weeeeeb [17]

Answer:

No. These measures show a thinner team of NFL players according to the mean, variance, standard deviation, and quartiles.

Step-by-step explanation:

1) The measures of variation, namely The Range, Variance, Quartiles, Interquartiles, Sum of Squares, etc. shows us how the data are dispersed.

The Range Δ is calculated:

\Delta =305-189=116 Maximum value - Minimum value for weight

Mean:

\bar{x}=\frac{189+254+235+225+190+305+202+190+252+305}{11}\approx 231.09 \:pounds

Variance:

s^{2}=\frac{\sum_{i=1}^{n} (x_i-\bar{x})^{2}}{n-1}\Rightarrow s=1923.69\\

The Standard Deviation of the sample

s=\sqrt{s^{^{2}}}\Rightarrow s\approx 43.86\\

2) Since there is no preceding exercise, the comparison was made to a recent study in which a NFL player average weight is about 245 pounds (average),

Since 25% of this list are player whose weight is 192.5 lbs and 50% (2nd Quartile) =225 lbs , finally only at the 3rd Quartile we have players above the regular NFL average with 253. This, added with the other data, allow us to say that this list is not a typical of all NFL players.

4 0
3 years ago
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