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Drupady [299]
3 years ago
5

Reyna has 7 coins worth 5 cents each and 3 coins worth 10 cents each.

Mathematics
2 answers:
DerKrebs [107]3 years ago
3 0

Found this. Hope it helps.

https://www.algebra.com/algebra/homework/word/coins/Word_Problems_With_Coins.faq.question.1059726.html

NemiM [27]3 years ago
3 0

Answer:

1/5

Step-by-step explanation:

because there is 10 coins and two specific coind you are trying to get and 2/10 simplified is 1/5

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Makovka662 [10]

Answer:

Caleb arrived first 2 hours before Alyssa

Step-by-step explanation:

To solve the situation, find the speed per hour they were driving by dividing the distance they drove by the time it took.

Alyssa drove 105 miles in 3.5 hours or 105/3.5 = 30 miles per hour.

Caleb drove 168 miles in 4 hours or 168/4 = 42 miles per hour.

Since they both left at the same time and drove the same 210 miles to the beach, Caleb arrived first since he was driving faster.

He arrived in 210/42 = 5 hours.

Alyssa arrived in 210/30 = 7 hours.

He arrived 2 hours before her.

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Ricco bought bagels for 6 people. He bought enough for everyone to have two bagels. How many bagels did he buy?​
Luba_88 [7]
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3 years ago
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Examine the following steps. Which do you think you might use to prove the identity Tangent (x) = StartFraction tangent (x) + ta
Over [174]

Answer:

The correct options are;

1) Write tan(x + y) as sin(x + y) over cos(x + y)

2) Use the sum identity for sine to rewrite the numerator

3) Use the sum identity for cosine to rewrite the denominator

4) Divide both the numerator and denominator by cos(x)·cos(y)

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Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

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(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

6 0
3 years ago
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