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GaryK [48]
4 years ago
13

What is 2.48 expressed as an improper fraction in simplest form?

Mathematics
2 answers:
bekas [8.4K]4 years ago
6 0

Answer: We can write 2.48 as \frac{62}{25} as an improper fraction in simplest form.

Step-by-step explanation:

Since we have given that

2.48 which we need to express as an improper fraction in simplest form.

So, we can write it as

2.48\\\\=2+\frac{48}{100}\\\\=2+\frac{48\div 4}{100\div 4}\\\\=2+\frac{12}{25}\\\\=\frac{50+12}{25}=\frac{62}{25}

So, we can write 2.48 as \frac{62}{25} as an improper fraction in simplest form.

oksian1 [2.3K]4 years ago
3 0
The answer is 62/25.

hope i helped^_^
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An amortized loan of RM60,000 has annual payments for fifteen years, the first occurring exactly one year after the loan is made
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9514 1404 393

Answer:

  a) RM2256.09 . . . principal paid by 8th payment

  b) RM1791.10 . . . . interest paid by 12th payment

Step-by-step explanation:

First of all, we need to find the payments.

The payment amount is the amount that makes the future value of the series of payments equal to the future value of the loan at the given interest rate.

The future value of a single amount is ...

  FV = P(1 +r)^n . . . . . where r is the annual rate, and n is the number of years in the future

The future value of a series of payments is ...

  FV = P((1 +r)^n -1)/r . . . . . where n is the number of payments of P earning annual rate r

For payments in a series that does not end at the end of the loan, the future value is the product of that of the series and the effect of the accumulation of interest for the remaining time.

__

The first 4 payments will have a future value at the end of the loan period of ...

  s1 = X((1 +0.05)^4 -1)/0.05×(1 +0.05)^11 = X(1.05^15 -1.05^11)/0.05

  s1 = 7.3717764259X

The next 5 payments will have a future value at the end of the loan period of ...

  s2 = 2X((1 +0.05)^5 -1)/0.05×(1 +0.05)^6 = 2X(1.05^11 -1.05^6)/0.05

  s2 = 14.8097486997X

The last 6 payments will have a future value at the end of the loan period of ...

  s3 = 4X((1 +0.05)^6 -1)/0.05 = 27.20765125X

So, the total future value of the series of payments is ...

  payment value = 7.3717764259X +14.8097486997X +27.20765125X

  = 49.3891763756X

__

The future value of the loan amount after 15 years is ...

  loan value = 60,000(1 +0.05)^15 = 124,735.69

In order for these amounts to be the same, we must have ...

  49.3891763756X = 124,735.69

  X = 124,735.69/49.3891763756 = 2,525.57

__

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<em>Additional comment</em>

The spreadsheet "goal seek" function could be used to find the payment amount that makes the loan balance zero at the end of the term.

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