Answer:
x == y
How? :
So in this case for recursion to stop, the program needs to reach a base case. A base case is a situation where coming across that line of code will give a certain output, meaning it will definitely give an output and not go back into to the program. For example, if you have a program very similar to yours with recursion, and the program continues to run until it hits the value 1. Now, say you had specified in the code for the method that if the int (integer) value of the int variable x equals 1, the code would return 1. This situation in java would look like:
if (x == 1) return 1;
<em>or</em>
if (x == 1){
return 1;
}
This is what you would call a base case. Now, if you were to enter two values into the method for your code, what would you get? Let's say you enter 3 and 6 (3 for int x, and 6 for int y). In this case the value of variables x and y would satisfy the code, and recursion would occur, where outputs continue to loop until you hit a wall, where output satisfies a base case. For your situation, a base case would be where x can be less than five, y can be greater than five, but, most importantly, x and y do not satisfy the condition where x != y. If you don't know what that means, x != y means "x is not equal to y". So for the values of x and y to not not be equal (sorry if this is confusing), the values of x and y have to be equal. Now, if you were to pug in 6 and 6 in your code, you would an output of just one line - "y: 6" and nothing else. Tada! Recursion has ended since the output has satisfied a base case - "x and y are equal" i.e. x == y . Thus, the correct answer would be x == y. Hope my explanation helped.
Take care,
Somebody
