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blondinia [14]
3 years ago
7

The java compiler is able to find all programmer errors.

Computers and Technology
1 answer:
Troyanec [42]3 years ago
5 0
No compiler can do that. Maybe with AI, but that's beyond the scope of a compiler.
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- Explain the Windows User Authentication process for Client connecting to the domain
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Write a function called median, that takes as parameter a full, sorted array of doubles and returns the median of the list. For
trapecia [35]

Answer:

Explanation:

public class Lab8

{

public static double median(double list[])

{

int size=list.length;

if(size%2!=0)

return list[size/2];

else

return(list[size/2-1]+list[size/2])/2.0;

}

public static boolean issorted(double list[])

{

for(int i=0;i<list.length-1;i++)

{

if(list[i]>list[i+1])

return false;

}

return true;

}

public static void findcommon(int a1[],int a2[],int common[])

{

int c=0;

for(int i=0;i<a1.length;i++)

{

boolean isFilled=false;

for(int j=0;j<c;j++)

{

if(a1[i]==common[j])

{

isFilled=true;

break;

}

}

if(isFilled)

{

for(int k=0;k<a2.length;k++)

{

if(a1[i]==a2[i])

{

common[c]=a1[i];

c++;

break;

}

}

}

}

while(c<common.length)

{

common[c]=0;

c++;

}

}

public static void rotateRight(int list[])

{

int temp=list[list.length-1];

for(int i=list.length-1;i>0;i--)

{

list[i]=list[i-1];

}

list[0]=temp;

}

public static int count(int list[],int n)

{

int ncount=0;

for(int i=0;i<list.length;i++)

{

if(list[i]==n)

ncount++;

}

return ncount;

}

public static int[] stretch(int list[])

{

int stretchedList[]=new int[list.length*2];

int k=0;

for(int i=0;i<list.length;i++)

{

int n=list[i];

if(n%2==0)

{

stretchedList[k]=n/2+1;

stretchedList[k+1]=n/2;

}

k+=2;

}

return stretchedList;

}

public static void printDoubleArray(double arr[])

{

System.out.print("[");

for(int i=0;i<arr.length;i++)

{

if(i!=arr.length-1)

System.out.print(arr[i]+",");

else

System.out.print(arr[i]);

}

System.out.println("]");

}

public static void printIntArray(int arr[])

{

System.out.print("[");

for(int i=0;i<arr.length;i++)

{

if(i!=arr.length-1)

System.out.print(arr[i]+",");

else

System.out.print(arr[i]);

}

System.out.println("]");

}

public static void main(String[] args)

{

double list1[]={1.1,2.2,3.3,4.4,5.5,6.6};

double med=median(list1);

System.out.println("List1:");

printDoubleArray(list1);

System.out.println("Median of List1:"+ med);

double list2[]={1.1,2.2,3.3,4.4,6.6,5.5};

boolean result=issorted(list2);

System.out.println("List2:");

printDoubleArray(list2);

System.out.println("List2 is a sorted array.(T/F):"+ result);

int list3[]={3,8,5,6,5,8,9,2};

int list4[]={5,15,4,6,7,3,9,11,9,3,12,13,14,9,5,3,13};

int list5[]=null;

if(list3.length<=list4.length)

list5=new int[list3.length];

else

list5=new int[list4.length];

findcommon(list3,list4,list5);

System.out.println("\n List3:");

printIntArray(list3);

System.out.println("\n List4:");

printIntArray(list4);

System.out.println("\n Array with common value,List5:");

printIntArray(list5);

int list6[]={3,8,19,7};

System.out.println("\n List6:");

printIntArray(list6);

rotateRight(list6);

System.out.println("\n the array after rotate right:");

printIntArray(list6);

int list7[]={3,5,2,1,92,38,3,14,5,73};

int n=count(list7,3);

System.out.println("\n List7:");

printIntArray(list7);

System.out.println("\n the number of occurences of the value 3 in the list 7:"+ n);

int list8[]={18,7,4,24,11};

int list9[]=stretch(list8);

printIntArray(list8);

System.out.println("\n The array after stretching:");

printIntArray(list9);

}

}

8 0
3 years ago
In JavaScript, which of the statements below can be used for string declaration?
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Complete the problem about Olivia, the social worker, in this problem set. Then determine the telecommunications tool that would
denis23 [38]

Answer:

PDA is the correct answer to the following answer.

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