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grandymaker [24]
3 years ago
13

What is the length of AC? ОЗft o4ft 9 ft 09 ft o18 ft

Mathematics
2 answers:
yKpoI14uk [10]3 years ago
8 0

Answer:

18ft

Step-by-step explanation:

Nezavi [6.7K]3 years ago
4 0

Answer:

18 ft

Step-by-step explanation:

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A vase in the shape of an oblique cylinder has the dimensions shown. What is the volume of the vase?
fenix001 [56]

The image is missing so i have attached it.

Answer:

Volume = 1.5 litres

Step-by-step explanation:

Using pythagoras theorem, we can get the height (h) of the cylinder

14² + h² = 17²

h² = 289 - 196

h = √93

Now, volume of a cylinder is;

V = πr²h

In the image, r = diameter/2 = 14/2 = 7cm

Thus,

V = π × 7² × √93

V = 1485 cm³

Now, 1 litre = 1000 cm³

Thus, volume = 1485/1000 = 1.485 litres ≈ 1.5 litres

5 0
3 years ago
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Which of the following statements are correct based on the diagram? Select all that apply.
cluponka [151]

Answer:

Segment U T is congruent to segment X V

Segment S T is congruent to segment W V

Angle V is congruent to angle T

7 0
2 years ago
A garage charges $24 an hour for labour. The garage charges Nigel $336 labour to replace the engine in his car. For how many hou
Lelechka [254]

Answer:

14 hours

Step-by-step explanation:

336/$24 = 14 hours

8 0
3 years ago
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Please help me with this question​
Alex Ar [27]

5/6 or 83% (roughly, since probability is never exact).

(hope this helps!)

6 0
3 years ago
What is a cubic polynomial function in standard form with zeroes 1, –2, and 2?
Lisa [10]
Starting off with the polynomial in standard form would be extremely difficult, but we can construct one fairly easily with the zeroes we've been given.

We know from the given zeroes that our function has the value 0 when x = 1, x = -2, and x = 2. Manipulating each equation, we can rewrite them as x - 1 = 0, x + 2 = 0, and x - 2 = 0. To construct our polynomial, we simply use all three of the expressions on the left side of the equation as factors and multiply them together, obtaining:

(x-1)(x+2)(x-2)=0

Notice that we can easily obtain each our three zeroes by dividing both sides by the two other factors. From here, we just need to expand the left-hand side of the equation. I'll show the work required here:

(x-1)(x+2)(x-2)=0\\
\big[(x-1)x+(x-1)2\big](x-2)=0\\
(x^2-x+2x-2)(x-2)=0\\
(x^2+x-2)(x-2)=0\\
(x^2+x-2)x-(x^2+x-2)2=0\\
x^3+x^2-2x-(2x^2+2x-4)=0\\
x^3+x^2-2x-2x^2-2x+4=0\\
x^3+(x^2-2x^2)+(-2x-2x)+4=0\\
x^3-x^2-4x+4=0\\

So, in standard form, our cubic polynomial would be x^3-x^2-4x+4
3 0
4 years ago
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