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Artist 52 [7]
3 years ago
5

The slope of a line is2/3 . What is the slope of a line that is perpendicular to this line? A-3/2 B-2/3 C2/3 D3/2

Mathematics
2 answers:
slamgirl [31]3 years ago
4 0

Answer:

i believe it is C

Step-by-step explanation:

Tomtit [17]3 years ago
4 0

Answer:

A

Step-by-step explanation:

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{2}{3} } = - \frac{3}{2} → A

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finlep [7]
1. See the attached graph.

2. All translations are considered rigid motion. The locations of points on the figure do not change relative to one another.

7 0
3 years ago
Malcolm is trying a very low-carbohydrate diet. He would like to keep the amount of carbs consumed in grams between the levels s
Ostrovityanka [42]

Answer:

The correct option is 2.

Step-by-step explanation:

The given inequalities are

50             .... (1)

2x+10            .... (2)

Solve each inequality.

Subtract 10 from each side of inequality (1).

50-10

40

Divide both the sides by 2.

20

The value of x is more than 20.

Subtract 10 from each side of inequality (2).

2x+10-10

2x

Divide both the sides by 2.

x

The value of x is less than 50.

Since x > 20 and x < 50, therefore Malcolm needs to consume more than 20 grams of carbohydrates, but less than 50 grams of carbohydrates.

Hence the correct option is 2.

4 0
3 years ago
For each level of precision, find the required sample size to estimate the mean starting salary for a new CPA with 95 percent co
Rzqust [24]

Answer:

(a) Margin of error ( E) = $2,000 , n = 54

(b)   Margin of error ( E) = $1,000 , n = 216

(c)   Margin of error ( E) = $500 , n= 864

Step-by-step explanation:

Given -

Standard deviation \sigma = $7,500

\alpha = 1 - confidence interval = 1 - .95 = .05

Z_{\frac{\alpha}{2}} =  Z_{\frac{.05}{2}} = 1.96

let sample size is n

(a) Margin of error ( E) = $2,000

Margin of error ( E)  = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

                           E   = Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

E^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{2000^{2}} \times 7500^{2}

n =  54.0225

n = 54 ( approximately)

(b)   Margin of error ( E) = $1,000

          E     = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

         1000   =  Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

1000^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{1000^{2}} \times 7500^{2}

n = 216

(c)   Margin of error ( E) = $500

   E = Z_{\frac{\alpha}{2}}\frac{\sigma}{\sqrt{n}}

  500 = Z_{\frac{.05}{2}}\frac{7500}{\sqrt{n}}

Squaring both side

500^{2} = 1.96^{2}\times\frac{7500^{2}}{n}

n =\frac{1.96^{2}}{500^{2}} \times 7500^{2}

n = 864

7 0
3 years ago
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sweet [91]
7.5 is 30 percent of 25 because

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6 0
3 years ago
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omeli [17]

Answer:

see below

Step-by-step explanation:

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17. -10 = -√100 and -11 = -√121 so -√120 is in between -10 and -11. Since 120 is closer to 121, the answer is -11.

5 0
3 years ago
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