3 years ago

3x^2 − 16x + 2 = 0

1 answer:

6 0

A = 3 b = -16 and c = 2
the radicand would be
sq root (b^2 -4*a*c) =
sq root (256 -4*3*2) =
sq root (232)
So the roots will be real and not complex.

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