Answer:
246
Step-by-step explanation:
i got it right on my test
The term in the expansion:
T ( k+1) = n C k * A^(n-k) * B^k.
In this case: n = 11, k + 1 = 8, so k = 7.
A = x, B = - 3 y
T 8 = 11 C 7 * x^(11-7) * ( - 3 y )^7 =
=( 11 *10 * 9 * 8 * 7 * 6 * 5 ) / ( 7 * 6 * 5 * 4 * 3 * 2 * 1 )* x^4 * ( - 2,187 y^7 ) =
= 330 * ( - 2,187 ) x^4 y^7 = - 721,710 x^4 y^7
Answer: The 8th term in expansion is
Answer:
$25000
Step-by-step explanation:
If the salvage value is 20% of the cost, then 80% of the cost will be depreciated over 10 years. Over the 5 years from Jan 1 20X1 to Dec 31 20X5, the $10,000 accumulated depreciation represents 5/10 of that 80%, or 40% of the initial cost.
$10,000 = 0.40 × cost
$10,000/0.40 = cost = $25,000
The acquisition cost of the equipment was $25,000.
40x=356000 x= 8900 applications
you make x the number of total applications
Answer:
Y = 1/4x - 5
Step-by-step explanation:
Slope (m = y2-y1 / x2-x1) is 1/4 and using one point substituting it instead of x and y you get y - intercept of -5.
Hope this helps. Pls give brainliest.
