```
#!/usr/local/bin/python3
import sys
def print_factorial( user_val ):
if( user_val < 1 ):
return( 1 )
else:
return( print_factorial( user_val - 1 ) * user_val )
if( __name__ == "__main__" ):
if( len( sys.argv ) == 2 ):
print( print_factorial( int ( sys.argv[ 1 ] ) ) )
else:
sys.stderr.write( "usage: %s <integer>\n" % sys.argv[ 0 ] )
exit( 0 )
```
Answer:
import java.util.Scanner;
public class Supermarket
{
public static void main (String[] args)
{
String item;
double pounds, ounces, price,
total, unit;
Scanner scn = new Scanner(System.in);
System.out.print("Please enter the name of item ");
item = scn.nextLine();
System.out.print("Please enter the price of " + "the item per pound : ");
price = scn.nextDouble();
System.out.print("Enter the weight of " + "the item in pounds and " + "ounces respectively : ");
pounds = scn.nextDouble();
ounces = scn.nextDouble();
unit = price/16;
total = price * (pounds + ounces/16);
System.out.print("The unit price of " + "the products sold is : " + unit);
System.out.print("\nThe total cost of the " + "amount purchased is : " + total);
}
}
Explanation:
- Ask the user to enter the price of the item and the weight.
- Calculate the unit and the total price.
- Display the unit and the total price.
Answer:
We first need to find out the number of variables, and if it is 3 or less, we can use excel for visualization or else we need to make use of the Microsoft Power BI or Tableau. And here, we have one variable as subscribers in various age groups, and the second variable is the number of hours spent in watching videos. And hence, we have only two variables. And thus, we can make use of the bar chart for visualization, and that is quite enough for visualizing this case. However, remember visualization is done for analyzing, and analyzing is made easy through visualization.
Explanation:
Please check the answer.
Answer:
Redundant networks are generally more reliable.
Explanation:
Answer:
count = 0;
longest =0;
String myString = new String();
while (input.hasNext()){
myString = input.next();
if (myString.length() == longest) count++;
else
if (myString.length() > longest){
longest = myString.length();
count = 1;
}
}
Explanation:
