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mestny [16]
2 years ago
13

A business that subscribes to a specific computing model has its entire system fully functional within a short time. What benefi

t of cloud computing does this scenario address?
A. easy access
B. easy collaboration
C. economies of scale
D. quick deployment
Computers and Technology
2 answers:
Dvinal [7]2 years ago
8 0

Its quick development

Quick deployment: When a business opts for cloud computing and subscribes to a specific model, (its entire system can be fully functional within a short time)—even within a few minutes. The amount of time depends on the kind of technology and the business’s computing needs.


ASHA 777 [7]2 years ago
6 0

Answer

economies of scale

Explanation

Cloud computing  is the practice of using a network of remote servers hosted on the Internet to store, manage, and process data, rather than a local server or a personal computer.  Benefits of moving everyday business to the cloud is that it can provide small businesses with significant savings. In cloud computing Virtualization increases the value of physical server hardware, meaning businesses can do more with less.Business that subscribes to a specific computing model has its entire system fully functional within a short time  will have economies of scale benefit. This is because this will be consuming information technology that can lead to significant cost saving.


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Answer:

In Java:

import java.util.Scanner;  

import java.util.Arrays;  

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public static void main(String args[])  {  

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public static int[] findmax(int[][] Array2D,int row, int col)   {  

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Explanation:

The next two lines import the scanner and array libraries

<em>import java.util.Scanner;   </em>

<em>import java.util.Arrays;   </em>

The class of the program

<em>public class Main  {  </em>

The main method begins here

<em>public static void main(String args[])  {  </em>

The scanner function is called in the program

<em>Scanner input = new Scanner(System.in);</em>

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input  

System.out.print("Rows: ");    row = input.nextInt();

This next instructions prompt the user for columns and get the column input  

System.out.print("Cols: ");     col = input.nextInt();  

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

<em> for(int i =0;i<row;i++){    </em>

<em>     for(int j =0;j<col;j++){ </em>

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<em>     }     } </em>

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This prints the row position

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}  

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int max = Array2D[0][0];

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The following iteration gets the position of the maximum element

<em>for(int i =0;i<row;i++){ </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         if(Array2D[i][j] > max){  </em>

<em>             maxitem[0] = i; </em><em>-- The row position is saved in index 0</em><em> </em>

<em>             maxitem[1] = j;  </em><em>-- The column position is saved in index 1</em><em>} }    } </em>

This returns the 1 d array

return maxitem;  

}  

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