How many bytes does a common processor require to represent an integer?

Your organization's network has multiple layers of security devices. When you attempt to connect to a service on the Internet. H

Sindrei [870]

Answer:

The host-based firewall settings are blocking the service

Explanation:

Host-based firewall settings can be configured on each workstation. The firewall can be provided by the operating system itself, or it can be a standalone software package that provides security features and functionality for the device's network connection. If this firewall contains incorrect settings, legitimate services can be blocked, and if so, a message will usually notify the user of such a breach. In these cases, the firewall settings need to be adjusted to make the desired service work.

7 0

3 years ago

In what form do the hexadecimal numbers need to be converted for a computer’s digital circuit to process them?

MrMuchimi

Hexadecimal numbers are just a convenient representation of binary data. When entered as text, they consist of ASCII characters 0-9 and a-f. The numbers will then have to be converted to binary. This is accomplished by converting to uppercase, subtracting the ASCII offset (48 for 0-9 or 55 for A-F), so that the result is a number between 0 and 15 (inclusive). This can be stored in computer memory to represent 4 bits.

Hexadecimal numbers represent binary numbers in the following way:

hex | binary

0 = 0000

1 = 0001

2 = 0010

3 = 0011

4 = 0100

5 = 0101

6 = 0110

7 = 0111

8 = 1000

9 = 1001

a = 1010

b = 1011

c = 1100

d = 1101

e = 1110

f = 1111

As you can see, no other 4 bit combination exists.

5 0

3 years ago

Which statement reflects an opinion about technology? Select all that apply. Select one or more: a. It is easy to imagine that a

True [87]

Answer:

All options apply to the question because each one reflects one side of technology in relation to the artist's case (that could be a software engineer or a even a hardware designer).

Explanation:

Letter a applies to the question in terms of computer program's behavior with no people's assistance, which is something not real for the present time, although it is easy to imagine that it is going to be a reality in a near future for all the improvements engineers and developers have made. Letter b also applies because computers and softwares have become one of the most important tools for artists around the world, whether for researching and/or for sharing and/or selling their productions, however it is a radical idea to think an artist is not necessary anymore, that is similiar to say human beings are not necessary only because machines have improved. Letter c also applies to the question for all improvements made in art and art forms after all improvements made in technology and tools for technologies development. And, letter d also applies because computers may be used for studying and/or working, which is the perfect tool for a workplace, and this is why it has become essential in many organizations, companies, subsidiaries, agencies, schools, and more.

3 0

3 years ago

A computer retail store has 15 personal computers in stock. A buyer wants to purchase 3 of them. Unknown to either the retail st

Dima020 [189]

Answer:

a. 1365 ways

b. Probability = 0.4096

c. Probability = 0.5904

Explanation:

Given

PCs = 15

Purchase = 3

Solving (a): Ways to select 4 computers out of 15, we make use of Combination formula as follows;

$^nC_r = \frac{n!}{(n-r)!r!}$

Where $n = 15\ and\ r = 4$

$^{15}C_4 = \frac{15!}{(15-4)!4!}$

$^{15}C_4 = \frac{15!}{11!4!}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12 * 11!}{11! * 4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{15 * 14 * 13 * 12}{4 * 3 * 2 * 1}$

$^{15}C_4 = \frac{32760}{24}$

$^{15}C_4 = 1365$

Hence, there are 1365 ways 

Solving (b): The probability that exactly 1 will be defective (from the selected 4)

First, we calculate the probability of a PC being defective (p) and probability of a PC not being defective (q)

From the given parameters; 3 out of 15 is detective;

So;

$p = 3/15$

$p = 0.2$

$q = 1 - p$

$q = 1 - 0.2$

$q = 0.8$

Solving further using binomial;

$(p + q)^n = p^n + ^nC_1p^{n-1}q + ^nC_2p^{n-2}q^2 + .....+q^n$

Where n = 4

For the probability that exactly 1 out of 4 will be defective, we make use of

$Probability = ^nC_3pq^3$

Substitute 4 for n, 0.2 for p and 0.8 for q

$Probability = ^4C_3 * 0.2 * 0.8^3$

$Probability = \frac{4!}{3!1!} * 0.2 * 0.8^3$

$Probability = 4 * 0.2 * 0.8^3$

$Probability = 0.4096$

Solving (c): Probability that at least one is defective;

In probability, opposite probability sums to 1;

Hence;

Probability that at least one is defective + Probability that at none is defective = 1

Probability that none is defective is calculated as thus;

$Probability = q^n$

Substitute 4 for n and 0.8 for q

$Probability = 0.8^4$

$Probability = 0.4096$

Substitute 0.4096 for Probability that at none is defective

Probability that at least one is defective + 0.4096= 1

Collect Like Terms

Probability = 1 - 0.4096

Probability = 0.5904

8 0

2 years ago

Router 1 is configured with static NAT. Addressing on the router and the web server are correctly configured, but there is no co

marin [14]

Answer:

The router NAT configuration has an incorrect inside local address.

Explanation:

The term Inside in a Network Address Translation (NAT) context refers to networks owned by an organisation that must be translated. When NAT is configured, hosts within this network have addresses in one space (known as the local address space). These hosts appear to those users outside the network as being in another space (known as the global address space).

The term Outside refers to those networks to which the stub network connects, and which are not under the control of an organisation. Also, hosts in outside networks can be subject to translation, and can thus have local and global addresses

7 0

2 years ago