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3 years ago

How do you write -3x-3y=-15 in a y=mx+b format

Mathematics

1 answer:

3241004551 [841]3 years ago

8 0

The answer should be y= -x+5

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1. Write a polynomial function of minimum degree with real coefficients whose zeros include those listed. Write the polynomial i

Katena32 [7]

Polynomial with real coefficients always has even number of complex roots. We know that one of them is 2 + 5i so the second one will be 2 - 5i and:

$f(x)=\big(x-4\big)\big(x-(-8)\big)\big(x-(2+5i)\big)\big(x-(2-5i)\big)=\\\\=(x-4)(x+8)(x-2-5i)(x-2+5i)=\\\\=(x^2-4x+8x-32)(x^2-2x+5ix-2x+4-10i-5ix+10i-25i^2)\\\\=\big(x^2+4x-32\big)\big(x^2-4x+4-25\cdot(-1)\big)=\\\\=(x^2+4x-32)(x^2-4x+29)=\\\\=x^4-4x^3+29x^2+4x^3-16x^2+116x-32x^2+128x-928=\\\\=\boxed{x^4-19x^2+244x-928}$

Answer B.

8 0

3 years ago

Read 2 more answers

Which of these quadrilaterals have opposite sides that are parallel? Name these quadrilateral

Ad libitum [116K]

Answer:

square,rectangle,rhombus,paralellagram

Step-by-step explanation:

4 0

3 years ago

State the inverse of the ordered pair:(−8,3).

nevsk [136]

Answer:

i d k

Step-by-step explanation:

4 0

3 years ago

Factor this expression

Julli [10]

Answer:

6(6x^2-4x-3)

Step-by-step explanation:

pull out the gcf which is 6 and it is complete because it is impossible to factor 6x^2-4x-3

5 0

2 years ago

Read 2 more answers

Please hepl with math

Ivenika [448]

Answer:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}$

Step-by-step explanation:

We are given the expression to be simplified:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}}$

Let us take common a term with a power of 5 from the numerator and the denominator of the given expression.

We know that:

$a^{p+q} = a^p \times a^q$

Let us use it to solve the powers of 5 in the given expression.

$\therefore$ we can write:

$5^{n+2} = 5^{n+1}\times 5= 5^n\times 5^{2}$

$5^{n+1} = 5^n\times 5$

The given expression becomes:

$\dfrac{5^{n+1} \times 5-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n}\times 5}$

Taking common $5^{n+1}$ from the numerator and

Taking common $5^{n}$ from the denominator

$\Rightarrow \dfrac{5^{n+1} (5-6)} {5^{n}(13-2\times5)}\\\Rightarrow \dfrac{5^{n+1} (-1)} {5^{n}(13-10)}\\\Rightarrow -\dfrac{5^{n+1}} {5^{n}\times3}\\\Rightarrow -\dfrac{5^{n}\times 5} {5^{n}\times3}\\\Rightarrow -\dfrac{5}{3}$

$\therefore$ The answer is:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}$

6 0

3 years ago