3 years ago

PLEASE HELP with proving lines parallel

Mathematics

1 answer:

den301095 [7]3 years ago

4 0

90 mins later we had to go to sleep for sub for two other people that were not

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Use the triangle below to find cos V.

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Answer:

$cos\ V = \frac{2\sqrt{29}}{29}$

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

$cos\theta = \frac{Adjacent}{Hypotenuse}$

In this case:

$cos V= \frac{TV}{UV}$

Where

$TV = 6$

and

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Take square roots

$UV = \sqrt{261$

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$UV = \sqrt{9} *\sqrt{29$

$UV = 3\sqrt{29$

So:

$cos V= \frac{TV}{UV}$

$cos\ V = \frac{6}{3\sqrt{29}}$

$cos\ V = \frac{2}{\sqrt{29}}$

Rationalize:

$cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}$

$cos\ V = \frac{2\sqrt{29}}{29}$

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The sum of 1/6, 2/3, and 1/4 is

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First, make all the denominators same.
Then calculate.
Hopefully this helps :D

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