Common Pythagorean triples include
(3, 4, 5)
(5, 12, 13)
(7, 24, 25)
(9, 40, 41)
The only Pythagorean triple that is an arithmetic sequence is (3, 4, 5), so any arithmetic sequence that is a Pythagorean triple must be a multiple of that, such as (9, 12, 15) or (15, 20, 25).

The arithmetic sequences of selections B and D are unrelated to the (3, 4, 5) triple, so cannot be Pythagorean triples. For selection A, we know that 9² + 11² = 81 + 121 = 202 > 14², so that is not a right triangle.

The appropriate selection is ...
C. 7, 24, 25

8 0

3 years ago

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Given segment AC and point B that lies on AC,

ololo11 [35]

The total length of the segment AC is the sum of AB and CB, which gives, CB = 9

<h3>How can the length of CB be found?</h3>

The given parameters are;

AC = 17
AB = 32 + 3•x
CB = 57 + 6•x

Required: <em>CB</em>

Solution:

AC = <em>AB + CB</em> by segment addition property

Therefore;

AC = 17 = 32 + 3•x + 57 + 6•x = 89 + 9•x

17 = 89 + 9•x

$x = \frac{17 - 89}{9} = - 8$

CB = 57 + 6•x = 57 + 6 × (-8) = 9

Therefore;

<u>CB = 9</u>

Learn more about segment addition postulate here: brainly.com/question/1721582

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8 0

2 years ago

Help plz:)))I’ll mark u Brainliest

MArishka [77]

This a right triangle shown above

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3 years ago

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