There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:
So 5 people and (3) could be considered as 6 entities:
Since the order matters, we have to use permutation:
¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!
2,162,160 x 6 = 12,972,960 ways.
Another way to solve this problem is as follow:
5 + (3) people are considered (for the time being) as 6 entities:
The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways
So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:
Total number of permutation = 2,162,160 x 6 = 12,972,960
7*4=28
7-4=3
so the width is 4 feet and the length is 7 feet
Answer:
440 seagulls
Step-by-step explanation:
Total number of seagulls in flock = Number of seagulls have banded / Percentage of seagulls have banded
Total number of seagulls in flock = 22 / 5%
Total number of seagulls in flock = 22 / 0.05
Total number of seagulls in flock = 440 seagulls
4) 247÷19=13
base is 13in
7)0.2÷0.4=0.5
height is pop. 5in
formula to find area for a parrallelogram is A=b×h
if you need to find base or height the divide area by height or base
Answer:
Step-by-step explanation:
Since she buys lunch for 15 days you do 12.35 times 15 which is $185.25
