Exponental law
so
√(81y^5)=√81 times √(y^5)
√81=9 or -9
√(y^5)=y^2 times√y
answer is 9y^2 times √y or -9y^2 times √y
You would solve this by determining how many numbers from 1-10 can be multiples of 5. That's obviously 5 and 10. So that's 2/10 or reduced to 1/5. Now the second question you have to find how many numbers from 1-10 are prime. Prime is a number that can only be divided by 1 and itself. So that would leave you with 1, 3, 5, 7. I think where the trick comes into play is if you drew a 5 or 10 the first time, then you didn't place those cards back in the box, you couldn't draw them again. So the answer would 4/10 or 2/5 if you could draw the 5 again. Or I supposed if you had drew the 10 the first time and not the 5. I assume however, they want you to exclude 5 and 10 because it was part of the first section of this equation. So that would mean only 1, 3, and 7 or 3/10.
What grade are you in cause like
The answer would be positive if all 3 signs were the same. Yes, the product of two integers with the same sign will be positive, but that goes for any number of integers as long as they still have the same sign.
Answer:
12.86 m/s
Step-by-step explanation:
Centripetal acceleartion formula:
