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alexandr1967 [171]
3 years ago
8

Are two squares with the same side lengths scaled copies of one another?

Mathematics
2 answers:
Natalija [7]3 years ago
8 0

Yes. Any square is a scaled copy of any other. The scale factor for two same-size squares is 1.

Andreas93 [3]3 years ago
7 0

1. A figure that shows a real figure with accurate sizes reduced or enlarged by a certain amount (the scale factor) is called scale copy.

2. Two figures are congruent if they are the same size and shape - that is, if their corresponding angles and sides are equal (or scaled copies with scale factor 1).

3. Square is a quadrilateral that has equal sides and every angle is a right angle (90°).

If you have two squares with the same side lengths, then they have

  • congruent corresponding sides (they are all equal);
  • congruent corresponding angles (they are all right).

This means that  two squares with the same side lengths are congruent or are scaled copies of each other (with scale factor 1).

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the inequality 1/2x+3<2x-6 is equivalent to) A. x<-5/6 B. x<6 C. x>-5/6 D. x>6 explain and show work please ​
Lunna [17]

Answer:

<h2>D. x > 6</h2>

Step-by-step explanation:

\dfrac{1}{2}x+3

8 0
3 years ago
What is the answer to this 2√3-5√÷√3+2√5​
Burka [1]

Answer:

\sqrt{ \div 3}

mathematicallly error sentence!

4 0
3 years ago
Read 2 more answers
From sea level, a submarine descends 20 feet per minute. Where is the submarine in relation to sea level 5 minutes after it star
Katen [24]
The correct answer is C.) 100 feet

(Feet per minute) x (number of minutes)

20x5 = 100
4 0
4 years ago
If every student in a large Statistics class selects peanut M&amp;M’s at random until they get a red candy, on average how many
kotykmax [81]

Question:

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You randomly select peanut M&M's from an extra-large bag looking for a red candy.

If every student in a large Statistics class selects peanut M&M’s at random until they get a red candy, on average how many M&M’s will the students need to select? (Round your answer to two decimal places.).

Answer:

If every student in the large Statistics class selects peanut M&M’s at random until they get a red candy the expected value of the number of  M&M’s the students need to select is 8.33 M&M's.

Step-by-step explanation:

To solve the question, we note that the statistical data presents a geometric mean. That is the probability of success is of the form.

The amount of repeated Bernoulli trials required before n eventual success outcome or

The probability of having a given number of failures before the first success is recorded.

In geometric distribution, the probability of having an eventual successful outcome depends on the the completion of a certain number of attempts with each having the same probability of success.

If the probability of each of the preceding trials is p and the kth trial is the  first successful trial, then the probability of having k is given by

Pr(X=k) = (1-p)^{k-1}p  

The number of expected independent trials to arrive at the first success for a variable Xis 1/p where p is the expected success of each trial hence p is the probability for the red and the expected value of the number of trials is 1/p or where p = 12 % which is 0.12

1/p = 1/0.12 or 25/3 or 8.33.

4 0
3 years ago
The area of a triangle is 1440cm^2 the base of tge triangle is 5 times the height of the triangle
Oduvanchick [21]
What should we find...
Probably base and the height...

Area = 1440cm²

base = 5×height

base = 5h

Area of triangle = base × height

1440 = 1/2 × 5h × h

1440 = 5h²/2

5h² = 2880

h² = 2880/5

h² = 576

h=24cm..

Height = 24cm

Since base = 5h

Base = 5×24

Base = 120cm...

Hope this helped....

Base =
4 0
3 years ago
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