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alexandr1967 [171]
3 years ago
8

Are two squares with the same side lengths scaled copies of one another?

Mathematics
2 answers:
Natalija [7]3 years ago
8 0

Yes. Any square is a scaled copy of any other. The scale factor for two same-size squares is 1.

Andreas93 [3]3 years ago
7 0

1. A figure that shows a real figure with accurate sizes reduced or enlarged by a certain amount (the scale factor) is called scale copy.

2. Two figures are congruent if they are the same size and shape - that is, if their corresponding angles and sides are equal (or scaled copies with scale factor 1).

3. Square is a quadrilateral that has equal sides and every angle is a right angle (90°).

If you have two squares with the same side lengths, then they have

  • congruent corresponding sides (they are all equal);
  • congruent corresponding angles (they are all right).

This means that  two squares with the same side lengths are congruent or are scaled copies of each other (with scale factor 1).

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James wants to buy some CDs that cost $14 each and a DVD that costs $23. He has $65. Write an equation (in the Show your work ar
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Write the equation of the sphere in standard form. x^2 + y^2 + z^2 + 2x − 4y − 6z = 22
madam [21]

The equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Given equation of sphere be x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We are required to express the given equation in the standard form of the equation of sphere.

Equation is basically relationship between two or more variables that are expressed in equal to form. Equation of two variables look like ax+by=c. It may be linear equation,quadratic equation, cubic equation or many more depending on the powers of variables. The standard form of the equation of sphere looks like  x^{2} +y^{2} +z^{2} =r^{2}.

The given equation is x^{2} +y^{2} +z^{2} +2x-4y-6z=22.

We have to break 22 which is in right side into various parts according to the left side of the equation.

x^{2} +y^{2} +z^{2} +2x-4y-6z=-1-4-9+36

x^{2} +y^{2} +z^{2} +2x-4y-6z+1+4+9=36

x^{2} +1+2x+y^{2}+4-4y+z^{2} +9-6z=36

x^{2} +(1)^{2} +2*1*x+y^{2} +(2)^{2} -2*2y+z^{2} +(3)^{2} -2*3z=36

(x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}

Hence the equation x^{2} +y^{2} +z^{2} +2x-4y-6z=22  in standard form looks like (x+1)^{2} +(y-2)^{2} +(z-3)^{2} =(6)^{2}.

Learn more about equations at brainly.com/question/2972832

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