Answer:
1. z = 128
2. x = 4.2
3. c = 10
4. w = 100
5. a = 95.2
Step-by-step explanation:
1. Solve for z:
z/16 = 8
Multiply both sides of z/16 = 8 by 16:
(16 z)/16 = 16×8
(16 z)/16 = 16/16×z = z:
z = 16×8
16×8 = 128:
Answer: z = 128
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2. Solve for x:
3.5 x = 14.7
Divide both sides of 3.5 x = 14.7 by 3.5:
(3.5 x)/3.5 = 14.7/3.5
3.5/3.5 = 1:
x = 14.7/3.5
14.7/3.5 = 4.2:
Answer: x = 4.2
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3. Solve for c:
32 = 3.2 c
32 = 3.2 c is equivalent to 3.2 c = 32:
3.2 c = 32
Divide both sides of 3.2 c = 32 by 3.2:
(3.2 c)/3.2 = 32/3.2
3.2/3.2 = 1:
c = 32/3.2
32/3.2 = 10:
Answer: c = 10
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4. Solve for w:
(2 w)/5 = 40
Multiply both sides of (2 w)/5 = 40 by 5/2:
(5×2 w)/(2×5) = 5/2×40
5/2×2/5 = (5×2)/(2×5):
(5×2)/(2×5) w = 5/2×40
5/2×40 = (5×40)/2:
(5×2 w)/(2×5) = (5×40)/2
(5×2 w)/(2×5) = (2×5)/(2×5)×w = w:
w = (5×40)/2
2 | 2 | 0
| 4 | 0
- | 4 |
| | 0
| - | 0
| | 0:
w = 5×20
5×20 = 100:
Answer: w = 100
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5. Solve for a:
a/14 = 6.8
Multiply both sides of a/14 = 6.8 by 14:
(14 a)/14 = 14×6.8
(14 a)/14 = 14/14×a = a:
a = 14×6.8
14×6.8 = 95.2:
Answer: a = 95.2
Answer:
3.2
Step-by-step explanation:
11.5 - 5.1 = 6.4
6.4 ÷ 2 = 3.2
Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
Answer:
g-4
Step-by-step explanation:
first subtract 7 from both sides
then you will get -4
g
which is the same as g
-4
you just have to switch them
