Answer:
Step-by-step explanation:
I assume that you mean
sec(x)-tan(x) = 1 / ( sec(x) + tan(x) ) , right ?
then this is equivalent to
[ sec(x) - tan(x) ] x [ sec(x) + tan(x) ] = 1
let s evaluate it, we got
sec2(x) - sec(x)tan(x) + - sec(x)tan(x) - tan2(x) = sec2(x) - tan2(x)
= (1 - sin2(x) ) / cos2(x) = cos2(x) / cos2(x) = 1
as cos2(x) + sin2(x) = 1
To find the x-intercepts algebraically, we let y = 0 y=0 y=0 in the equation and then solve for values of x. In the same manner, to find for y-intercepts algebraically, we let x = 0 x=0 x=0 in the equation and then solve for y.
F(b)=7b+8
you just need to change the x variable. make y into f(x) or in this case f(b)
2s+5<span>≥49
First: Subtract 5 on both sides
You'll get: 2s </span><span>≥ 44
Last: Divide each side by 2 so your s would be alone
You'll get: s </span><span>≥ 22 <That would be your answer
HOPE THIS HELPS! ^_^</span>
