Answer:
t=14
v=13
q=12
s=23
w=-4
x=28
Step-by-step explanation:
we know that the universal set =100
so, everything in it must add up to 100
first, from the information given to us,
t= n(A n C)= 14
v=n(B n C)= 13
to find q
we know from our guide that n(A) =40
which means everything inside A will add up to 40
therefore,
q + 7 + 7 + t = 40
and we already know that t = 14
so, that will be;
q + 7 + 7 + 14 = 40
therefore, q = 12
to find s,
we all know that n(B) = 50
which means that everything inside B will be equal to 50
therefore,
s + 7 + 7 + v = 50
and we know that v = 13
therefore,
s + 7 + 7 + 13 = 50
and s will end up to be = 23
to find w,
we know that n(C) = 30
so, everything in C end up to be all equal to 30
therefore,
t + 7 + w + v = 30
from our solution, t = 14, v = 13
so,
14 + 7 + w
Answer:
c<-3
Step-by-step explanation:
move the constant to the right-hand side and change its sing
Then canculate the difference
Then divide both sides for the inequality of 3
Slope-intercept form:
y=mx+b
m=slope
b=y-intercept
We have this line: y=9x+3; a line parallel to this line (y=9x+3) will have the same slope; therefore m would be equal to 9 (m=9).
Data:
m=9
b=-2
y=mx+b
y=9x-2
Answer: y=9x-2
So for this problem you know that 15 is 1/4 of an hour so to get the amount of papers each individual could deliver by themselves in an hour you would multiply the amount they can deliver in 15 minutes by 4. Denny delivers 6 so multiplying that by 4 is 24. Next Brendan delivers 5 in 15 minutes so multiplying that by 4 you get 20. The final step is to add 20 and 24 to get the total amount of papers between the two of them that gets delivered in an hour. This will result in your answer of 44.
