Volume of pyramid:
A - base area
H - height
First count volume of one pyramid:
![V=\dfrac{1}{3} \cdot 3 \cdot 4=4 [\hbox{inch}^3]](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7D%20%5Ccdot%203%20%5Ccdot%204%3D4%20%5B%5Chbox%7Binch%7D%5E3%5D)
So by using 576 inch^3 you can make 576 : 4 =
144 pyramids
<h3>
Answer: UF = 11</h3>
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Explanation:
In EFU, we see that EU are the first and last letters. In VWU, we see that VU are the first and last letters. This order is important to be able to pair EU with VU
So EU/VU is one ratio
The other ratio is UF and UW, which are the last two letters of EFU and VWU respectively. So the other ratio is UF/UW
Set the ratios equal to each other and solve for x
EU/VU = UF/UW
7/35 = x/55
7*55 = 35*x ... cross multiply
385 = 35x
35x = 385
x = 385/35 .... divide both sides by 35
x = 11
UF = 11
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Or you could note how UV = 35 is exactly 5 times larger compared to EU = 7
That must mean WU = 55 must also be 5 times larger compared to UF = x
So,
WU = 5*UF
55 = 5x
5x = 55
x = 55/5
x = 11
UF = 11
This is similar to the previous section because UV/EU = 35/7 = 5 is the scale factor.
Answer:
of the 4 people that have a sister, 2 of them have a brother
Step-by-step explanation:
probability of B given A
given that the person has a sister, what is the probability they have a brother
P (B/A) = 1/2
with this venn diagram
of the 4 people that have a sister, 2 of them have a brother
Answer:
D
Step-by-step explanation:
Differentiate the function and set it to zero:
f'(x) = -10x + 13
0 = -10x + 13
x = 1.3 seconds
Plug the x value into f(x):
f(1.3) = -5(1.3)^2 + 13(1.3) + 6 = 14.45 meters
If the equation of the circle is x^2+ y^2 = 41, we must first understand the parts of the equation.
A general circle's equation is (x-h)^2+(y-k)^2= r^2
(h.k) is the radius of the circle
r is the radius of the circle
Another useful fact to know is that tangent lines touch the circle at one point (4,5)
Since in our original equation there are no h or k values, we can assume that the center of the circle is (0,0).
The formula for slope is <u>Y1-Y2</u>
X1-X2
We can break this down with our two points (center and tangent)
(0,0) and (-4,-5)
(X1,Y1) and (X2,Y2)
therefore, we will put the equation as such
<u>0-(-5)= 5</u> = <em> </em><u><em>5</em></u>
0-(-4)= 4 <em> 4</em>
<em>this is our slope from the center to the point of tangency.</em>
We know that tangent lines are perpendicular to the radius, which we've already found the slope of. Perpendicular lines are opposite reciprocals of the line they are perpendicular to.
Therefore, we take our slope from center to the tangent, and make it opposite and then take the reciprocal of that slope, which will give us the slope of the tangent line itself. (note: reciprocal means flip the numerator and denominator)
<u>5</u> = <u>-5</u> = <u>-4</u><u>
</u>4 4 5
Now, we have a point on the line, and the line's slope. We can use slope-intercept equation to find the equation of the line.
Slope-int y=mx+b
(x,y) is a point,
m is the slope
b is the y intercept ( the point where x=0, or where its on the y axis)
now we plug things in
(-4,-5) is our point,
<u>-4</u> is our slope
5
-5=<u>-4</u>(-4)+b After we plug things in, solve for b
5
-5= 3.2+b
-1.8= b or b= <u />1 <u>4</u>
5
Now we just need to rewrite our equation with all our components.
(-4.-5) = point
<u>-4</u> = slope<u>
</u>5
1 <u>4</u> = y-intercept<u>
</u> 5
<em>y=</em><u><em>-4</em></u><em> x+ 1 </em><u><em>4</em></u><em> This is the equation of the tangent line</em><u>
</u><em> 5 5</em>
Hope that helped
