A few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil. so, the correct answer is option A.
<h3>What is the Rutherford experiment?</h3>
Rutherford performed an experiment in which alpha particles are bombarded on the gold foil.
Some of the particles bounced back which indicates that there are heavy particles present in the center of an atom.
Most alpha particles pass through the atom which indicates that there is a lot of empty space in an atom.
A few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil. so, the correct answer is option A.
Learn more about the atomic model ;
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Answer:
accelerate / increase speed OR decelerate / decrease speed OR stop B1
change direction / move in a curve o.w.t.t.e
Explanation:
accelerate / increase speed OR decelerate / decrease speed OR stop B1
change direction / move in a curve o.w.t.t.e
Answer:
Options (3) and (6)
Explanation:
Janine drives 2.2 km East.
Since, distances measured in the East are positive,
Displacement = 2.2 km
Then she drives 4.4 km west
Displacement = -4.4 km
Followed by 1.7 km in the East
Displacement = 1.7 km
Total displacement = 2.2 - 4.4 + 1.7 = -0.5 km
km
Total distance covered by Janine = 2.2 + 4.4 + 1.7 = 8.3 km
d = 8.3 km
Therefore, Options (3) and (6) will be the answer.
Answer:
a) t1 = v0/a0
b) t2 = v0/a0
c) v0^2/a0
Explanation:
A)
How much time does it take for the car to come to a full stop? Express your answer in terms of v0 and a0
Vf = 0
Vf = v0 - a0*t
0 = v0 - a0*t
a0*t = v0
t1 = v0/a0
B)
How much time does it take for the car to accelerate from the full stop to its original cruising speed? Express your answer in terms of v0 and a0.
at this point
U = 0
v0 = u + a0*t
v0 = 0 + a0*t
v0 = a0*t
t2 = v0/a0
C)
The train does not stop at the stoplight. How far behind the train is the car when the car reaches its original speed v0 again? Express the separation distance in terms of v0 and a0 . Your answer should be positive.
t1 = t2 = t
Distance covered by the train = v0 (2t) = 2v0t
and we know t = v0/a0
so distanced covered = 2v0 (v0/a0) = (2v0^2)/a0
now distance covered by car before coming to full stop
Vf2 = v0^2- 2a0s1
2a0s1 = v0^2
s1 = v0^2 / 2a0
After the full stop;
V0^2 = 2a0s2
s2 = v0^2/2a0
Snet = 2v0^2 /2a0 = v0^2/a0
Now the separation between train and car
= (2v0^2)/a0 - v0^2/a0
= v0^2/a0