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DiKsa [7]
3 years ago
14

Large and small numbers are often best entered in exponential notation. For example, the mass of the earth is 5.98x1024 kg and t

he mass of an electron is 9.11x10-31 kg. Canvas does not have the capability to handle scientific notation. We will include the power of 10 with the units needed in the answer. The charge of an electron is -1.60x10-19 C. Determine the charge to mass ratio of the electron (in 1011 C/kg). (Hint: divide the electron's charge by its mass; the answer is a negative number with a positive exponent)
Physics
2 answers:
stich3 [128]3 years ago
5 0

Answer:

The charge to mass ratio is

m/e= -0.17*10^12kg/c

Explanation:

Step one :

Given data

mass of an electron m= 9.11x10-31kg

charge of electron q= -1.60x10-19C

Applying the equation

mv²/r=Bev

Where m =mass of charge

v= velocity of charge

r= distance

B=magnetic field

e= charge

Rearranging to get the charge-mass ratio we have

mv²/r=Bev

m/e=Br/v

(-1.60x10-19)/(9.11x10-31kg)=Br/v

-0.17*10^12

m/e= -0.17*10^12kg/c

Doss [256]3 years ago
4 0

Answer:

The charge to mass ratio is -1.76\times10^{11}

Explanation:

Mass\ of\ electron=m_e=9.11\times10^{-31} kg\\ Charge\ of\ the\ electron=q_e=-1.60\times10^{-19} C\\

We need to find how much charge is contained  in the electron per unit of mass, to do this we divide the charge in an electron and the mass of an electron:

\frac{Charge\ of\ electron}{Mass\ of\ electron}=\frac{q_e}{m_e}\frac{C}{kg}=\frac{-1.60\times10^{-19} C}{9.11\times10^{-31} kg}=-1.76\times10^{11} \frac{C}{kg}

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2 years ago
An object is moving in a straight line at a constant speed. A resultant force begins to act upon the object. State the ways in w
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3 years ago
{WORTH BRAINLIEST WITH AN EXPLANATION} Janine is a police officer patrolling a street. She drives 2.2 km east, then 4.4 km west,
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Answer:

Options (3) and (6)

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4 years ago
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0 = v0 - a0*t

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B)

How much time does it take for the car to accelerate from the full stop to its original cruising speed? Express your answer in terms of v0 and a0.

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C)

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Answer:

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