Answer:
The intensity of the earthquake in Chile was about 16 times the intensity of the earthquake in Haiti.
Step-by-step explanation:
Given:
magnitude of earthquake in Chile =  8.2 
magnitude of earthquake in Haiti = 7.0
To find: 
Compare the intensities of the two earthquakes
Solution:
The magnitude R of earthquake is measured by R = log I 
R is basically the magnitude on Richter scale
I is the intensity of shock wave
For Chile:
given magnitude R of earthquake in Chile =  8.2 
R = log I 
8.2 = log I
We know that:
 is equivalent to:
  is equivalent to:  
  
 
 
8.2 = log I becomes:

So the intensity of the earthquake in Chile:

For Haiti:
R = log I 
7.0 = log I
We know that:
 is equivalent to:
  is equivalent to:  
  
 
 
7.0 = log I becomes:

So the intensity of the earthquake in Haiti:

Compare the two intensities :
 
 

= 
= 
= 15.848932
Round to the nearest whole number:
16
Hence former earthquake was 16 times as intense as the latter earthquake.
Another way to compare intensities:
Find the ratio of the intensities i.e.  
 
 -
 -  = 8.2 - 7.0
 = 8.2 - 7.0
 = 1.2
 = 1.2 
Convert this logarithmic equation to an exponential equation
 = 1.2
 = 1.2
 =
 =  
 
Hence
 = 16
  = 16