Answer:
![(2,8]](https://tex.z-dn.net/?f=%282%2C8%5D)
Step-by-step explanation:
Given
The attached piece wise function
Required
The domain
To do this, we simply consider the inequalities that bound the values of x.
The inequalities are:
and 
Combine the first two inequalities:
and 
For the inequality to be true, we must have:

In interval notation, the inequality is:
![(2,8]](https://tex.z-dn.net/?f=%282%2C8%5D)
Answer:
A function can have many x values for a given y value and still be a function but it cannot have many y values for a given x value. You can easily test this by graphing the equation and doing the vertical line test by seeing if a vertical line will intersect the graph only once at all x values, if it passes it is a function. In short what you have here is a function
Step-by-step explanation:
Answer:
Children: $13
Adults: $18
Step-by-step explanation:
Well for both sets we can set up the following system of equations,

So first we need to solve for a in the first equation.
3a + 4c = 106
-4c to both sides
3a = -4c + 106
Divide 3 by both sides
<u>a = -4/3c + 35 1/3</u>
Now we plug in that a for a in 2a + 3c = 75.
2(-4/3c + 35 1/3) + 3c = 75
-8/3c + 70 2/3 + 3c = 75
Combine like terms
1/3c + 70 2/3 = 75
-70 2/3 to both sides
1/3c = 4 1/3
Divide 1/3 to both sides
c = 13
Now we can plug in 13 for c in 3a + 4c = 106,
3a + 4(13) = 106
3a + 52 = 106
-52 to both sides
3a = 54
Divide 3 by both sides.
a = 18
<em>Thus,</em>
<em>an adult ticket is $18 and a children's ticket is $13.</em>
<em />
<em>Hope this helps :)</em>
It would be 82 2/3 since 1/3 minis 2/3 would equal -1/3 you subtract that from 83 and get 82 2/3