Answer:
35.8 g
Explanation:
Step 1: Given data
Mass of water: 63.5 g
Step 2: Calculate how many grams of KCl can be dissolved in 63.5. g of water at 80 °C
Solubility is the maximum amount of solute that can be dissolved in 100 g of solute at a specified temperature. The solubility of KCl at 80 °C is 56.3 g%g, that is, we can dissolve up to 56.3 g of KCl in 100 g of water.
63.5 g Water × 56.3 g KCl/100 g Water = 35.8 g KCl
Hope this helps!
https://youtu.be/MT5tKijKZwQ
Answer: Through extensive bonding
Explanation:
Oxidation of two cysteine gives disulphide bonds. They are covalent in nature. Given as;
R-CH2-SH + R'-CH2 +02 = R-CH2-S-S-CH2-R' + H202
They are the stabilizing force behind protein folding the endoplasmic reticulum. Proteins being the backbone of our genetic constitution require disulphide bonding to stabilize the peptide molecules and the extent and number of this bonding determines the Resistance of the protein molecule to extreme conditions e.g extreme heat which denatures proteins and elasticity as well.
Answer:
I don't know any except helium, sorry I couldn't do much.
