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2 years ago

The general term used by archaeologists for a pin that was used in holding a garment together is the roman word ________.

1 answer:

6 0

The general term used by archaeologists for a pin that was used in holding a garment together is the roman word Fibula.
The term Fibula refers to Roman brooches, but also denotes brooches from the entire ancient period.

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What pattern do we see when looking at the fossil record? *

iogann1982 [59]

Answer:

Organisms become more complex over time.

Explanation:

We all evolved from the first bacteria, which was relatively simple. We see over time that things become more adapted, slowly adding eyes, lungs, behavioral patterns, and consciousness.

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2 years ago

What is the balanced equation for the combustion of magnesium?

Lostsunrise [7]

Answer:

2Mg + O2 → 2MgO

Explanation:

In all conbustion you should know, that reactans are an specific compound and O2, so the products must be CO2 and H2O, or in this case, the corresponding oxide.

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3 years ago

Draw the diagram of 4-propylnonane

andriy [413]

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2 years ago

Calcium chloride forms an ionic solid. how are the particles held together and arranged in the solid

Advocard [28]

Calcium chloride forms an ionic compound with a regularly arranged lattice of oppositely charged ions.

The Na+ and Cl- ions are held together by strong electrostatic forces.

Hope that helps

7 0

2 years ago

Read 2 more answers

Convert the following Grams: 0.200 moles of H2S

ANEK [815]

Answer:

6.82 g H₂S

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Chemistry

Atomic Structure

Reading a Periodic Table

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

0.200 mol H₂S

Step 2: Identify Conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of H₂S - 2(1.01) + 32.07 = 34.09 g/mol

Step 3: Convert

Set up: $\displaystyle 0.200 \ mol \ H_2S(\frac{34.09 \ g \ H_2S}{1 \ mol \ H_2S})$
Multiply: $\displaystyle 6.818 \ g \ H_2S$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

6.818 g H₂S ≈ 6.82 g H₂S

7 0

2 years ago