Question

Solve each system of equations by the substitution method 3x+4=-y; 2x +y=0

Answer 1

Answer:

Step-by-step explanation:

3x+4=−y

3x+4+y=−y+y(Add y to both sides)

3x+y+4=0

3x+y+4+−3x=0+−3x(Add -3x to both sides)

y+4=−3x

y+4+−4=−3x+−4(Add -4 to both sides)

y=−3x−4

Step: Substitute−3x−4foryin2x+y=0:

2x+y=0

2x+−3x−4=0

−x−4=0(Simplify both sides of the equation)

−x−4+4=0+4(Add 4 to both sides)

−x=4

−x

−1

=

4

−1

(Divide both sides by -1)

x=−4

Step: Substitute−4forxiny=−3x−4:

y=−3x−4

y=(−3)(−4)−4

y=8(Simplify both sides of the equation)

Answer:

x=−4 and y=8