I think the answer is letter c
Answer:
Both Law of Sines and Cosines can be used to determine the angle Q.
Step-by-step explanation:.
Since from Law of Sines with one angle and three sides we can find other angles using the ratio obtained with the given angle and side length opposite side if angle P is not given we couldn't use this.
Law of Cosines can be used to find any angle of triangle with all three side lengths given and angle P is also not required to find angle Q.
3x+3-x+(-7)>6
combine like terms on left side
2x-4>6
add 4 to both sides 2x>10
x=10/2 = 5
x>5
Answer:
<em>− 2sin(b) / cos(2b)</em>
Step-by-step explanation:
DIFFERENTIATE W.R.T. B is a different method entirely
We simply add together the numerators and set with 2cos
then keep this number and add to sinb and square it.
then repeat initial 2 + cosb ^2 but instead of multiplying its add.
Then set the whole division to -sin (2b) squared then +1
<em> − 2cos(b)(3(sin(b))^2+(cos(b))^2) / −(sin(2b)) ^2 +1 </em>
You can use the equation rise over Run you go up 4 and over 6 and you go down 2 and over 8 (im not sure if this helps)
