Fill in the blanks with two consecutive integers to complete the following inequality.

Which expression has a value of 12? A. 3+32 B. 32 +23 C. (4+2)2 D. 42-32

alekssr [168]

The answer is C because if you multiply 4 and 2 by 2 it would become 8 and 4, 8+4=12

4 0

3 years ago

Write fraction in "Simpilist Form". If already , then write "Simpilist Form". The Fraction is: 3 over 100 - 3/100

dezoksy [38]

Answer:

see explanation

Step-by-step explanation:

A fraction is in simplest form when no other factor but 1 will divide into the numerator/ denominator

(1)

$\frac{3}{100}$ ← is in simplest form

(2)

$\frac{2}{5}$ ← is in simplest form

(3)

$\frac{10}{12}$ ( divide numerator/ denominator by 2 )

= $\frac{5}{6}$ ← in simplest form

8 0

3 years ago

Can someone please help me on number 16-ABC

melomori [17]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the inequality

-2x < 10

-6 < -2x

Part a) Is x = 0 a solution to both inequalities

FOR -2x < 10

substituting x = 0 in -2x < 10

-2x < 10

-3(0) < 10

0 < 10

TRUE!

Thus, x = 0 satisfies the inequality -2x < 10.

∴ x = 0 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 0 in -6 < -2x

-6 < -2x

-6 < -2(0)

-6 < 0

TRUE!

Thus, x = 0 satisfies the inequality -6 < -2x

∴ x = 0 is the solution to the inequality -6 < -2x

Conclusion:

x = 0 is a solution to both inequalites.

Part b) Is x = 4 a solution to both inequalities

FOR -2x < 10

substituting x = 4 in -2x < 10

-2x < 10

-3(4) < 10

-12 < 10

TRUE!

Thus, x = 4 satisfies the inequality -2x < 10.

∴ x = 4 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 4 in -6 < -2x

-6 < -2x

-6 < -2(4)

-6 < -8

FALSE!

Thus, x = 4 does not satisfiy the inequality -6 < -2x

∴ x = 4 is the NOT a solution to the inequality -6 < -2x.

Conclusion:

x = 4 is NOT a solution to both inequalites.

Part c) Find another value of x that is a solution to both inequalities.

solving -2x < 10

$-2x\:$

Multiply both sides by -1 (reverses the inequality)

$\left(-2x\right)\left(-1\right)>10\left(-1\right)$

Simplify

$2x>-10$

Divide both sides by 2

$\frac{2x}{2}>\frac{-10}{2}$

$x>-5$

$-2x-5\:\\ \:\mathrm{Interval\:Notation:}&\:\left(-5,\:\infty \:\right)\end{bmatrix}$

solving -6 < -2x

-6 < -2x

switch sides

$-2x>-6$

Multiply both sides by -1 (reverses the inequality)

$\left(-2x\right)\left(-1\right)$

Simplify

$2x$

Divide both sides by 2

$\frac{2x}{2}$

$x$

$-6$

Thus, the two intervals:

$\left(-\infty \:,\:3\right)$

$\left(-5,\:\infty \:\right)$

The intersection of these two intervals would be the solution to both inequalities.

$\left(-\infty \:,\:3\right)$ and $\left(-5,\:\infty \:\right)$

As x = 1 is included in both intervals.

so x = 1 would be another solution common to both inequalities.

<h3>SUBSTITUTING x = 1</h3>

FOR -2x < 10

substituting x = 1 in -2x < 10

-2x < 10

-3(1) < 10

-3 < 10

TRUE!

Thus, x = 1 satisfies the inequality -2x < 10.

∴ x = 1 is the solution to the inequality -2x < 10.

FOR -6 < -2x

substituting x = 1 in -6 < -2x

-6 < -2x

-6 < -2(1)

-6 < -2

TRUE!

Thus, x = 1 satisfies the inequality -6 < -2x

∴ x = 1 is the solution to the inequality -6 < -2x.

Conclusion:

x = 1 is a solution common to both inequalites.

7 0

3 years ago

100 points, I need help fast!

ivolga24 [154]

a. The standard error is equal to the standard deviation divided by the square root of the sample size:

SE = (23 ppm)/√18 ≈ 5.42 ppm

b. The t statistic is given by the difference between the true and sample means, divided by the standard error:

t = (192 ppm - 180 ppm)/SE ≈ 2.21

c. The p-value is approximately 0.0204.

d. Since p < 0.05, the difference is significantly different, so we reject the null hypothesis.

e. A type I error might have occurred, since it's possible that the null hypothesis was true, but we ended up rejecting it.

4 0

2 years ago

(hurry show ur work) what is 8 6/8 ÷ 2 2/5 = ?

gizmo_the_mogwai [7]

Answer:

175/48 or 3.64

Step-by-step explanation:

■ Refer to the attachment.

Hope it helps ⚜

4 0

2 years ago

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