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3 years ago

5999999-5999999+5+5+5+15+556

Mathematics

2 answers:

Lostsunrise [7]3 years ago

7 0

$(5999999-5999999)+(5+5+5+15)+556=0+30+556=586$

kap26 [50]3 years ago

5 0

The answer is 586 . And lmao did you just wanted to ask a question ?

You might be interested in

Is the equation y=3x proportional or non proportional?Explain.

solong [7]

Answer: Proportional

Step-by-step explanation:

y=3x is a proportional equation. If the value of x increases then y also increases. If the value of x decreases then y also decreases.

5 0

2 years ago

Are your finances, buying habits, medical records, and phone calls really private? A real concern for many adults is that comput

Andrej [43]

Answer:

a)There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

b)There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

c)There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

Step-by-step explanation:

The binomial probability is the probability of exactly x successes on n repeated trials in an experiment which has two possible outcomes (commonly called a binomial experiment).

It is given by the following formula:

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of a success.

In this problem, a success is being concerned that employers are monitoring phone calls.

53% of adults are concerned that employers are monitoring phone calls, so $p = 0.53$

(a) Out of four adults, none is concerned that employers are monitoring phone calls.

Four adults, so $n = 4$ .

Is the probability of 0 successes, so x = 0.

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

$P = C_{4,0}.(0.53)^{0}.(0.47)^{4}$

$P = 0.0488$

There is a 4.88% probability that none is concerned that employers are monitoring phone calls.

(b) Out of four adults, all are concerned that employers are monitoring phone calls.

Four adults, so $n = 4$ .

Is the probability of 4 successes, so x = 4.

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

$P = C_{4,0}.(0.53)^{4}.(0.47)^{0}$

$P = 0.0789$

There is a 7.89% probability that all are concerned that employers are monitoring phone calls.

(c) Out of four adults, exactly two are concerned that employers are monitoring phone calls.

Four adults, so $n = 4$ .

Is the probability of 4 successes, so x = 2.

$P = C_{n,x}.p^{n}.(1-p)^{n-x}$

$P = C_{4,2}.(0.53)^{2}.(0.47)^{2}$

$P = 0.3723$

There is a 37.23% probability that exactly two are concerned that employers are monitoring phone calls.

3 0

2 years ago

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down,drag into the correct p

boyakko [2]

Answer:

$\boxed{\sf \ \ 9x^2-18x-7 \ \ divided \ by \ (3x+1) \ is \ (3x-7) \ }$

Step-by-step explanation:

Hello,

let's find a and b reals so that

$9x^2-18x-7=(3x+1)(ax+b)$

$(3x+1)(ax+b)=3ax^2+(3b+a)x+b$

we identify the terms in $x^2$

9 = 3a

we identify the terms in x

-18 = 3b + a

we identify the constant terms

-7 = b

so ti goes with a = 9/3 = 3, b = -7

so we can write

$9x^2-18x-7=(3x+1)(3x-7)$

so $9x^2-18x-7 \ divided \ by \ (3x+1) \ is \ (3x-7)$

hope this helps

8 0

3 years ago

A helicopter is hovering 110 feet in the air over a landing pad. If a man sees the helecopter at an angle of elevation of 29°, w

Pavel [41]

See the attached figure to better understand the problem

we know that

tan 29°=AC/CB--------> CB=AC/tan 29°
AC=110 ft
CB--------> <span>how far the man is from the helicopter landing pad
</span>so
CB=AC/tan 29°----------> CB=110/ tan 29°----------> CB=198.45 ft

the answer is
the man is 198.45 ft from the helicopter landing pad