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BigorU [14]
3 years ago
6

Please show work very confused on how to get the answer

Mathematics
1 answer:
Liula [17]3 years ago
3 0
Their is no picture so heres s answer 2×2=4
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M ∠abd=87 M ∠abd=9x-1 M ∠cbd =6x+58
elena-s [515]

Answer:

there is no answer to this

Step-by-step explanation:

4 0
3 years ago
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Write 0.0002839 in scientific notation.
Anika [276]

Answer:2.84 x 10-4

There you go!

8 0
3 years ago
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What 0.04 percent form is?
sergij07 [2.7K]
4%
This is because 1 = 100%
0.4 would equal 40%
So 0.04 is 4%
3 0
3 years ago
Factor completely. (3.2² - 12x)(x2 – 2x + 1) =​
pychu [463]

Answer:

3x • (x - 4) • (x - 1)2

Step-by-step explanation:

5 0
2 years ago
To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

therefore

<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

therefore

<u>the answer Part 2) is</u>

Law of Cosines

3 0
2 years ago
Read 2 more answers
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