Answer:
-2
Step-by-step explanation:
f(x)=3x^2+5x-14
f(-3)=3(-3)^2+5(-3)-14
f(-3)=3(-3)(-3)-15-14
f(-3)=3(9)-29
f(-3)=27-29
f(-3)=-2
5 1/2 * 2 1/3 =
11/2 * 7/3 =
77/6 =
12 5/6 <===
Answer: B
4x^{6} - 2x^{5} + 4x^{3} -x^{2} +4x
Step-by-step explanation:
1) The function is
3(x + 2)³ - 32) The
end behaviour is the
limits when x approaches +/- infinity.3) Since the polynomial is of
odd degree you can predict that
the ends head off in opposite direction. The limits confirm that.
4) The limit when x approaches negative infinity is negative infinity, then
the left end of the function heads off downward (toward - ∞).
5) The limit when x approaches positive infinity is positivie infinity, then
the right end of the function heads off upward (toward + ∞).
6) To graph the function it is important to determine:
- x-intercepts
- y-intercepts
- critical points: local maxima, local minima, and inflection points.
7)
x-intercepts ⇒ y = 0⇒ <span>
3(x + 2)³ - 3 = 0 ⇒ (x + 2)³ - 1 = 0
</span>
<span>⇒ (x + 2)³ = -1 ⇒ x + 2 = 1 ⇒
x = - 1</span>
8)
y-intercepts ⇒ x = 0y = <span>3(x + 2)³ - 3 =
3(0 + 2)³ - 3 = 0 - 3×8 - 3 = 24 - 3 =
21</span><span>
</span><span>
</span><span>9)
Critical points ⇒ first derivative = 0</span><span>
</span><span>
</span><span>i) dy / dx = 9(x + 2)² = 0
</span><span>
</span><span>
</span><span>⇒ x + 2 = 0 ⇒
x = - 2</span><span>
</span><span>
</span><span>ii)
second derivative: to determine where x = - 2 is a local maximum, a local minimum, or an inflection point.
</span><span>
</span><span>
</span><span>
y'' = 18 (x + 2); x = - 2 ⇒ y'' = 0 ⇒ inflection point.</span><span>
</span><span>
</span><span>Then the function does not have local minimum nor maximum, but an
inflection point at x = -2.</span><span>
</span><span>
</span><span>Using all that information you can
graph the function, and I
attache the figure with the graph.
</span>
For the answer to the question above,
It seems the function f(x) is 3/(x+4).
If the function is f(x) = 3 / (x + 4), a table could be
x f(x)
-8 -3/4
-7 -1
-6 -3/2
-5 -1
(-4 is no a valid input)
- 3 3
- 2 3/2
-1 1
0 3/4
1 3/5
2 3/6 = 1/2
3 3/7
4 3/8
If the function is f(x) = (3/x) + 4
Just substitute different values for x and obtain the respective outputs. In this case, x has to be different of o, i.e. 0 is not a valid input.