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Delvig [45]
3 years ago
7

On a piece of paper,graph y+4

Mathematics
1 answer:
True [87]3 years ago
6 0
Well right now you have a linear function with 0 as a slope. The equation now is y+4=0 but in order to graph this, you subtract 4 to the right side to get the equation y= -4. This is now just a horizontal line extending in either direction on the grid where 4 is on the y axis.
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Plz help with this word problem
s344n2d4d5 [400]
Well, this problem is best solved by setting up a system of two linear equations.

A linear equation can be defined 
y=mx+b
where 
b=initial value (when x=0), and
m=rate of increase or decrease.

In the given example, the x-axis represents hour, and the y-axis, number of cells.

Chemical #1 
initial value = b = 12000 cells
rate = m = -4000 / hr
The equation is therefore 
y1=-4000x+12000......................(1)

Similarly, for chemical #2
initial value = b = 6000 cells
rate = m = -3000 / hr
The equation is therefore
y2=-3000x+6000 .......................(2)

The time the two will have an equal sized colony would represent the solution of the system of equations (1) and (2), i.e. when  y1=y2
which means
-4000x+12000 = -3000x+6000
transpose and solve for x
4000x-3000x = 12000-6000
1000x=6000
x=6 hours.

At 6 hours from the start, 
y=-4000x+12000 = -4000*6+12000 = -24000+12000 = -12000 cells

So the solution is x=6, y=-12000, or (6,-12000)

Physical interpretation
Since cells cannot have a negative number, the two are actually equal before six hours, when they are both zero.
Case 1: y=0 when x=3
Case 2: y=0 when x=2

Therefore, after three hours, both trials will have zero cells.

You have to judge whether to give the mathematical solution (x=6,y=-12000) or the physical interpretation (x=3, y=0) as the answer.


6 0
3 years ago
Read 2 more answers
Give an example of each of the following, or argue that such a request is impossible.
Masteriza [31]

Answer and Step-by-step explanation:

Solution:

(a) Let (bn) be a bounded sequence of (an) then, Bolzano- Weierstrass theorem,

(bn) contains a subsequence that is converges.

(b) The sequence :

Xn = 1 + (-1) n / 2 + 1/n

Clearly, (xn) does not contain 1 or 0.

If we take sequence (x2n), then it converges to 1 and when we take sequence (x2n+1),

Then it converges to 0.

(c) The sequence:

1

1,1/2

1, 1/2, 1/3

1, 1/2, 1/3, 1/4

i.e

(xn) = (1,1/2, 1, 1/2, 1/3, …)

Then, the subsequence (xn) that is identically ½ in second column and 1/3 is third column and so on.

It has sub sequence that converges to every point in infinite set {1, 1/2, 1/3, 1/4, 1/5…}.

(d) The sequence

{1, 1/2, 1/3, 1/4, 1/5…}

if we take sequence of given set, then, this set converges to zero. This is not contained in it.

If (xn) converges to every point in set {1, 1/2, 1/3 …} then there exists subsequence which converges to 0. And 0 does not belong to given set.

3 0
3 years ago
Can you show in a visual way ? Like graph or table ?
denpristay [2]

Answer:

Yes

Step-by-step explanation:

Just respond if you have a question

7 0
3 years ago
What is the correct answer for evaluate the expression 12 to 2nd power​
Leya [2.2K]

Answer:

144

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve for x.<br> x + 1 = 2<br> Ox= 1/4<br> O x= 1/2<br> O x = -1/2<br> 0 x = -1/4
Bogdan [553]

Answer:

x=-1/2

Step-by-step explanation:

7 0
3 years ago
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