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3 years ago

20-3x when x=2 and when x=3

Mathematics

2 answers:

hodyreva [135]3 years ago

8 0

When x=2 it’s 14
————————————————————
When x=3 it’s 11

Pani-rosa [81]3 years ago

7 0

When x = 2

20 - 3(2) = 14

When x = 3

20 - 3(3) = 11

Hope this helps :)

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An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do

vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

$P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107$

Then,

$P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007$

c) In this case, the distribution is B(1200,0.01)

$P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924$

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

$P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366$

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3 years ago

A florist can make a grand arrangement in 18 minutes or a simple arrangement in 10 minutes. The florist makes at least twice as

Colt1911 [192]

Answer:

See explanation

Step-by-step explanation:

Let x be the number of simple arrangements and y be the number of grand arrangements.

1. The florist makes at least twice as many of the simple arrangements as the grand arrangements, so

$x\ge 2y$

2. A florist can make a grand arrangement in 18 minutes $=\dfrac{3}{10}$ hour, then he can make y arrangements in $\dfrac{3}{10}y$ hours.

A florist can make a simple arrangement in 10 minutes $=\dfrac{1}{6}$ hour, so he can make x arrangements in $\dfrac{1}{6}x$ hours.

The florist can work only 40 hours per week, then

$\dfrac{3}{10}y+\dfrac{1}{6}x\le 40$

3. The profit on the simple arrangement is $10, then the profit on x simple arrangements is $10x.

The profit on the grand arrangement is $25, then the profit on y grand arrangements is $25y.

Total profit: $(10x+25y)

Plot first two inequalities and find the point where the profit is maximum. This point is point of intersection of lines $x=2y$ and $\dfrac{3}{10}y+\dfrac{1}{6}x=40$

But this point has not integer coordinates. The nearest point with two integer coordinates is (126,63), then the maximum profit is

$\$(10\cdot 126+25\cdot 63)=\$2,835$

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geniusboy [140]

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The root is equivalent to a fractional power with that number as the denominator. Otherwise, the rules of exponents apply.

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VMariaS [17]

Its1. every number/variable that has a power to the zero, its goin to turn out to be just one

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Determine whether the improper integral converges or diverges, and find the value of each that converges.

Ksju [112]

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