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Shalnov [3]
2 years ago
11

each of three students wrote an equation. • nikole wrote 5 2 = 21 8 4 • erik wrote 5.14 = 21 4 • keisha wrote 4 1 = 21 5 4 which

of these students wrote an equation that is true? staar 2013 a. nikole only. b. nikole and erik only. c. keisha only. d. nikole, erik, and keisha
Mathematics
1 answer:
ELEN [110]2 years ago
6 0
The answer is B. Keisha only
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The width of a rectangle measures (3.8b-1.5) centimeters, and it's length measures (4.3b-7.2) centimeters. Which expression repr
vivado [14]

Answer:

-17.4+16.2b

Step-by-step explanation:

I just guessed and it was right

6 0
2 years ago
How to graph y=-3x+15
steposvetlana [31]

Answer:

Well first you put the y-intercept on the graph. In this case it would be 15

So graph the point (0,15)

The you do the slope which is 3

so you always do rise over run for slope.

If 3 were a fraction it would be 3/1 so go up 3 points and the go right 1 point from (0,15)

hope this helps .-.

3 0
3 years ago
Twelve more than half of a number is equal to the number
tester [92]
Let's consider that number to be 'x'..
So, twice the number (2x) is 12 greater than than the half of the number.
So the equation will be like,
2x=12+x/2
Solving this further,
2x=(24+x)/2
=> 4x=24+x
=>4x-x=24
=>3x=24
=>x=8..
So the number is "8".
5 0
2 years ago
John is building a fence around his home currently his fence measures 14 feet on each side but he wants to increase only the wid
nalin [4]

Answer:

The dimensions of rectangular fence are 14 feet and 20 feet.

Step-by-step explanation:

We are given the following in the question:

Length of rectangular fence = 14 feet

Width of fence = (14+x) feet

Area of rectangular field = 280 square feet

Area of rectangular field =

A= \text{Length}\times \text{Width}

Putting the values, we get,

280 = 14(14+x)\\\\14 + x = \dfrac{280}{14}\\\\14 + x = 20\\x =20-14\\x = 6

Thus, the dimensions of rectangular fence are 14 feet and 20 feet.

7 0
2 years ago
What is the perimeter of the triangle in units of the triangle formed by the points (-3,1), (-3,5), and (4,1)?
ira [324]

let's say

A(-3,1) B(-3,5) C(4,1)

we need to find the perimeter of ABC for that we find each of the sides

AB BC and AC

there is a formula to find the distance between 2 poins

let's say that a point has the structure A(x1,y1) where x=-3 and y=1 and B(x2,y2) where x2=-3 and y2=5

AB=\sqrt{(x2-x1)^2+(y2-y1)^2}

AB=\sqrt{(-3+3)^2+(5-1)^2}

AB=\sqrt{0^2+4^2}

AB=4

we do the same thing for AC and BC

AC=\sqrt{(4+3)^2+(1-1)^2}

AC=\sqrt{7^2+0^2}

AC=7

BC=\sqrt{(4+3)^2+(1-5)^2}

BC=\sqrt{7^2+(-4)^2}

BC=\sqrt{49+16}

BC=\sqrt{65}

The perimeter is equal to the sum of the sides

P=AB+AC+BC=4+7+\sqrt{65}=11+\sqrt{65}

8 0
2 years ago
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