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Anarel [89]
4 years ago
14

A cylindrical container that contains three balls that are 2.7 inches in diameter is standing on its base and passes through an

x-ray scanner that scans from the top only. What outline will appear on the x-ray screen, and with what dimensions? cylindrical container with three spheres so that the spheres are stacked vertically on top of one another A rectangle that is 2.7 in x 8.1 in A rectangle that is 5.4 in x 8.1 in A circle with a diameter of 2.7 in A circle with a diameter of 5.4 in

Mathematics
1 answer:
Anna [14]4 years ago
6 0

Answer:

A circle with a diameter of 2.7 in

Step-by-step explanation:

I took the test its right

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Solve it please<br><br> 72:8
amm1812
9:1 because you divide both sides by 8. Hope this helps :)
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3 years ago
The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t
valentina_108 [34]
The answer is  0 < x <span>≤ 7 
</span>
First, we know that width =  x
Which means that length = x +18

So, the possible equation for the Table's area is

X (X + 18)  ≤ 175

X^2 + 18x - 175  <span>≤ </span>0

Next, we need to calculate is by using complete square method
x^2 + 18x + 81 <span>≤ 175 + 81

(x + 9)^2 </span><span>≤ 256

|x + 9| </span><span>≤ sqrt(256)

|x + 9| </span><span>≤ +-16

-16 </span>≤ x + 9 <span>≤ 16

</span>-16 - 9 ≤ x <span>≤ 16 - 9

</span>-25 ≤ x <span>≤ 7

Since the width couldn't be negative, we can change -25 with 0,

so it become
</span> 0 < x ≤ 7 
7 0
3 years ago
The answer to: expand and simplify 3x + 2 (x +5)
BARSIC [14]
Expanded: 3x^2 + 17x +10
Simply: it’s already simplified
4 0
3 years ago
In most microcomputers the addresses of memory locations are specified in hexadecimal. These addresses are sequential numbers th
iren [92.7K]

Considering that the addresses of memory locations are specified in hexadecimal.

a) The number of memory locations in a memory address range ( 0000₁₆ to FFFF₁₆ )  = 65536 memory locations

b) The range of hex addresses in a microcomputer with 4096 memory locations is ;  4095

<u>applying the given data </u>:

a) first step : convert FFFF₁₆ to decimal           ( note F₁₆ = 15 decimal )

( F * 16^3 ) + ( F * 16^2 ) + ( F * 16^1 ) + ( F * 16^0 )

= ( 15 * 16^3 ) + ( 15 * 16^2 ) + ( 15 * 16^1 ) + ( 15 * 1 )

=  61440 + 3840 + 240 + 15 = 65535

∴ the memory locations from  0000₁₆ to FFFF₁₆ = from 0 to 65535 = 65536 locations

b) The range of hex addresses with a memory location of 4096

= 0000₁₆ to FFFF₁₆ =  0 to 4096

∴ the range = 4095

Hence we can conclude that the memory locations in ( a ) = 65536 while the range of hex addresses with a memory location of 4096 = 4095.

Learn more : brainly.com/question/18993173

6 0
3 years ago
Find the GCF<br> 50x^4, -10x^5, 2x^6
shtirl [24]

Answer:

2 x^4

Step-by-step explanation:

Recall that the GCF is the greatest of the product of factors that are common to all these three expressions

then for the pure numerical part, the factor common to 50, -10 , and 2 is "2"

and for the variable part x^4 is the largest common to all three expressions.

Therefore the GCF is: 2 x^4

7 0
3 years ago
Read 2 more answers
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